Question

HELP PLS Triangle ABC has vertices located at A(0, 2), B (2,5), and C (-1, 7) Part A: Find the length of each side of the triangle. Show your work. (4 points) Part B: Find the slope of each side of the triangle. Show your work. (3 points) Part C: Classify the triangle. Explain your reasoning. (3 points)

Answer 1

Answer:

Hi!!

Step-by-step explanation:

So basically, you can use the distance formula to calculate the distances between the point on lines forming your triangle.  A picture would be helpful, however if Triangle ABC formed by lines AB, BC and AC you use the coordinates given.

d = SQRT((x2 - x1)^2 + (y2 - y1)^2)

A(0, 2), B(2, 5), C(-1, 7)

AB = SQRT((2 - 0)^2 + (5 - 2)^2)

AB = SQRT((2)^2 + (3)^2)

AB = SQRT(4 + 9)

AB = SQRT(13)

You can repeat the process for BC, and AC if you draw your triangle on a coordinate plane you can also count the distance between the points.

Hope this helps

Please let me know if I'm wrong✌