Answer:
<u>(x² + 4x + 6)/ 3x + 12</u>
<u>This is the most simplified form</u>
Step-by-step explanation:
Let's simplify the expression:
(x + 6)/(x + 4) + (x - 3)/3
Least Common Denominator : 3 * (x + 4)
[3 * (x + 6) + (x - 3) (x + 4)]/ 3 * (x + 4)
Solving parentheses:
[3x + 18 + x² - 3x + 4x - 12]/ 3 * (x + 4)
Like terms:
<u>(x² + 4x + 6)/ 3x + 12</u>
<u>This is the most simplified form</u>
Answer:
For bbff we have only 6.3% probability
Step-by-step explanation:
If the parents are heterozygous for both traits, them they are represented by:
BbFf × BbFf
Parent 1: BbFf
Parent 2: BbFf
We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.
By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:
Genotype Count Percent
bBfF 4 25
BBfF 2 12.5
bBFF 2 12.5
bBff 2 12.5
bbfF 2 12.5
BBFF 1 6.3
BBff 1 6.3
bbFF 1 6.3
bbff 1 6.3
For bbff we have only 6.3% probability
Because the student scored 73/100 on the first test, their current average is 73%.
To calculate the avergae with the next test score, you add both percentages the student gets together and then divide by 2.
79 = (73 + x) / 2
Multiply by 2 on both sides
158 = 73 + x
Subtract 73 on both sides
x = 85
So the student needs to get at least an 85/100 on the next test to maintain a 79 average.
There is no slope answer is = 0