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astra-53 [7]
3 years ago
15

This figure is a step in which construction?

Mathematics
2 answers:
Vikentia [17]3 years ago
4 0
<h2>Answer:</h2>

Option: B is the correct answer.

B.  a line perpendicular to <-AB-> through point P.

<h2>Step-by-step explanation:</h2>

We know that a line perpendicular to a given line is constructed as follows:

1)  Draw a line segment AB

2) Take a span of compass more than half the length of AB and keep the point of compass first at A and then at B to make a arc above AB.

3) Draw a straight line that passes through the intersection  of arc and line AB such that it meets AB at point P which will act as a midpoint of line AB.

       Hence, the correct option is:

                    Option: B

choli [55]3 years ago
3 0
This will give you many results. AP = PB by construction

C is a point made by making the compass points such that AC>AP and the compass points are not altered so that BC = AC

C when joined to P creates a perpendicular line. This is very important. You use it a lot. 
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What is the simplified form of the quantity of x plus 6, all over the quantity of x plus 4 + the quantity of x minus 3, all over
11Alexandr11 [23.1K]

Answer:

<u>(x² + 4x + 6)/ 3x + 12</u>

<u>This is the most simplified form</u>

Step-by-step explanation:

Let's simplify the expression:

(x + 6)/(x + 4) + (x - 3)/3

Least Common Denominator : 3 * (x + 4)

[3 * (x + 6) + (x - 3) (x + 4)]/ 3 * (x + 4)

Solving parentheses:

[3x + 18 + x² - 3x + 4x - 12]/ 3 * (x + 4)

Like terms:

<u>(x² + 4x + 6)/ 3x + 12</u>

<u>This is the most simplified form</u>

6 0
4 years ago
At 6 p.m., the temperature was 11°C 11°C. By midnight, the temperature was −3°C.-3°C.What is the difference between the two temp
zlopas [31]

Answer:

it's B

Step-by-step explanation:

14

5 0
4 years ago
Read 2 more answers
18. Brown eyes (B) are dominant to blue eyes (b). The presence of freckles (F) is dominant to the absence of freckles (f). What
MrRissso [65]

Answer:

For bbff we have only 6.3% probability

Step-by-step explanation:

If the parents are heterozygous for both traits, them they are represented by:

BbFf × BbFf

Parent 1: BbFf

Parent 2: BbFf

We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.

By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:

Genotype   Count     Percent  

bBfF  4     25

BBfF  2     12.5

bBFF  2     12.5

bBff          2     12.5

bbfF  2     12.5

BBFF  1     6.3

BBff      1            6.3

bbFF  1     6.3

bbff      1     6.3

For bbff we have only 6.3% probability

6 0
3 years ago
A student scores 73 out of 100 on a test. If the maximum score on the next test is also 100​ points, what score does the student
vesna_86 [32]
Because the student scored 73/100 on the first test, their current average is 73%.

To calculate the avergae with the next test score, you add both percentages the student gets together and then divide by 2.

79 = (73 + x) / 2

Multiply by 2 on both sides

158 = 73 + x

Subtract 73 on both sides

x = 85

So the student needs to get at least an 85/100 on the next test to maintain a 79 average.
3 0
3 years ago
Line has the equation y=
zlopas [31]
There is no slope answer is = 0
5 0
3 years ago
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