Question

Rewrite the equation by completing the square. x^2 + 2x - 8 = 0

Answer 1

Answer:

$\boxed{\sf \ \ (x+1)^2-9=0 \ \ }$

Step-by-step explanation:

hello,

we can notice that

$(x+1)^2=x^2+2x+1$

so

$x^2+2x=(x+1)^2-1$

and then

$x^2+2x-8=0\\ (x+1)^2-1-8=0\\\\ (x+1)^2=9\\ x+1=3 \ or \ x+1=-3\\ x=2 \ or \ x=-4$

solutions are 2 and -4

hope this helps