Answer:
297.1 mL of 1.0 M sodium sulfate has smallest number of ions.
Explanation:
A) 156.5 mL of 2.0 M iron(III) chloride
Volume of iron(III) chloride solution = 156.5 mL = 0.1565 L
Molarity of the iron(III) chloride = 2.0 M
Moles of iron(III) chloride = n
1 mole of iron(III) chloride gives 1 mol ferric ion and 3 mol chloride ions.
Number of ferric ions = 0.313 mol
Number of chloride ions = 0.313 mol × 3 = 0.939 mol
Total moles of ions = 1.252 moles
B) 521.4 mL of 1.0 M lithium nitrate:
Volume of lithium nitrate solution = 521.4 mL = 0.5214 L
Molarity of the lithium nitrate = 1.0 M
Moles of lithium nitrate = n
1 mole of lithium nitrate gives 1 mol lithium ion and 1 mol nitrate ions.
Number of lithium ions = 0.5214 mol
Number of nitrate ions = 0.5214 mol
Total moles of ions = 1.0428 mol
C) 374.3 mL of 2.0 M potassium hydroxide :
Volume of potassium hydroxide solution = 374.3 mL = 0.3743 L
Molarity of the potassium hydroxide = 2.0 M
Moles of potassium hydroxide = n
1 mole of potassium hydroxide gives 1 mol potassium ion and 1 mol hydroxide ions.
Number of potassium ions = 0.7486 mol
Number of hydroxide ions = 0.7486 mol
Total moles of ions = 1.4972 mol
E) 297.1 mL of 1.0 M sodium sulfate:
Volume of sodium sulfate solution = 297.1 mL = 0.2971 L
Molarity of the sodium sulfate = 1.0 M
Moles of sodium sulfate = n
1 mole of sodium sulfate gives 1 mol sodium ion and 2 mol sulafte ions.
Number of sodium ions = 0.2971 mol
Number of sulfate ions = 0.2971 mol × 2 = 0.5942 mol
Total moles of ion = 0.8913 mol
Higher the number of moles more with number of ions in the solution and vice-versa.
297.1 mL of 1.0 M sodium sulfate has smallest number of ions.