All categories

3 years ago

What is the use of oxyacetylene flame

Chemistry

2 answers:

harkovskaia [24]3 years ago

7 0

Answer:

An oxyacetylene torch can also be used for welding. When welding with an oxyacetylene torch, the flame is used to produce molten metal along the edge of two work pieces.

hope this helped

if you want plz give brainliest to help you more

statuscvo [17]3 years ago

4 0

Simple answer is

The oxyacetylene flame is a gas torch that burns a mixture of acetylene and oxygen to produce a high-temperature flame (3,000°C or 5,400°F) that can be used for welding, cutting steel, and other metal working.

You might be interested in

In the pie chart below, which of the following represents the amount of Earth's water located in the oceans?

Andrew [12]

Answer:

D. 97%

Explanation:

♪＼(*＾▽＾*)／＼(*＾▽＾*)／

4 0

3 years ago

Read 2 more answers

Please help me!!!!

miv72 [106K]

Answer:

0.8g/ml

Explanation:

d=m/v

d=20/25

d=0.8

7 0

3 years ago

Iron filings can be separated from a mixture with sulfur by using a magnet.

lbvjy [14]

The answer is A. True

3 0

3 years ago

Read 2 more answers

What volume in liters of carbon monoxide will be required to produce 18.9 L of nitrogen in the reaction below

mina [271]

Answer:

37.8 L OF CARBON MONOXIDE IS REQUIRED TO PRODUCE 18.9 L OF NITROGEN.

Explanation:

Equation for the reaction:

2 CO + 2 NO ------> N2 + 2 CO2

2 moles of carbon monoxide reacts with 2 moles of NO to form 1 mole of nitrogen

At standard temperature and pressure, 1 mole of a gas contains 22.4 dm3 volume.

So therefore, we can say:

2 * 22.4 L of CO produces 22.4 L of N2

44.8 L of CO produces 22.4 L of N2

Since, 18.9 L of Nitrogen is produced, the volume of CO needed is:

44.8 L of CO = 22.4 L of N

x L = 18.9 L

x L = 18.9 * 44.8 / 22.4

x L = 18.9 * 2

x = 37.8 L

The volume of Carbon monoxide required to produce 18.9 L of N2 is 37.8 L

8 0

3 years ago

Two common methods to generate an aldehyde is by oxidation of an alcohol and through ozonolysis.

kotykmax [81]

Answer:

a. True.

Explanation:

Only primary and secondary alcohols can oxidise to give an aldehyde. But a weak oxidizing agent must be used to prevent formation of a carboxylic acid or ketone.

weak oxidizing agents: Chromyl chloride, silver/oxygen/500°C

take an example of ethanol:

 ${ \bf{CH _{3} CH_{2}OH \: \: \frac{Ag/O_{2} }{500 \degree C} > \: \:CH _{3} CHO}}$ 

 ${ \sf{CH _{3} CHO \: \: is \: ethanal}}$ 

By ozonolysis:

Here, reactants are Ozone gas, Carbon tetrachloride at a temperature (<20°C), ethanoic acid, zinc and water.

take an example of propanol:

if it undergoes ozonolysis, it gives ethanal and methanal.

5 0

3 years ago

Read 2 more answers