You can use this formula to help:

Where:
C = specific heat
q = heat
m = mass
t = temperature
What we know:
C = unknown
q = 956 J
m = 45 g
change in t = 12°C because 37°C - 25°C = 12°C
Plug known values into the formula:
C = 956 J / (45 g) (12°C) and we are left with a specific heat of 1.77J/g°C
Now, convert Joules to calories and then you get:
Answer: A. 0.423 cal/g°C
Exothermic is when energy is released
endothermic is when its being absorbed<span />
Answer: The E for Silver-silver Chloride electrode = 0.287 V
Explanation:
Silver/Silver Chloride (Ag/AgCl) with a value for E° that is actually +0.222 V or approximately 0.23 V has the actual potential of the half-cell prepared in this way as +0.197 V vs SHE, (Standard Hydrogen Electrode) which arises because in addition to KCl, there is the contribuion of AgCl to the chloride activity, which isn't exactly unity.
Therefore, the E for the Ag/AgCl electrode would approximately equal 0.287 V