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bearhunter [10]
2 years ago
11

5. Consider the system of equation:

Mathematics
2 answers:
liubo4ka [24]2 years ago
7 0

Answer: A

Step-by-step explanation:

goldfiish [28.3K]2 years ago
3 0

Answer:
A

Step-by-step explanation:

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What is the solution to the system of equations graphed below???
german

Answer:

The solution is (-2,-2)

Step-by-step explanation:

This is the point where the two graphs intersect.

5 0
3 years ago
Through her bike 6 miles from her house to the library and then another two and 250 miles to her friend Milo's house and Carson'
Katarina [22]
25 ok i think that
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4 0
3 years ago
HELPPP!!!! Both questions are incredibly confusing to me !!!!!
Darya [45]

Answer:

Step-by-step explanation:

I'm going to start with problem 3. You need to become familar with the kind of tricks teachers play on you.

Problem 3 depends on getting RS = RW.

RT = RT                                    Reflexive property

<STR = <WTR                           A straight line having 1 rt angle  actually has 2

ST = TU                                    They are marked as equal

Triangle STR=Triangle WTR    SAS

RS = RW                                    Corresponding parts of = triangles are =

8x = 6x + 5                                Subtract 6x from both sides

8x -6x = 6x - 6x + 5                   Combine

2x = 5                                         Divide by 2

2x/2 = 5/2

x = 2.5

RU = 6*2.5 + 5

RU = 15 + 5

RU = 20

Now we can play with Question 4.

This question depends on the method used in three, although not entirely.

What you need to know is that W is on RT when you take a ruler and make RT longer. You can put W anywhere as long as it is on RT when it is made longer.

Directions

Make RT longer. Draw down and to your right.

Put a point anywhere on the length starting at T. Label this new point as W. There's your W. It goes anywhere on the part of RT made longer.

Draw UW.

Label UW as 8

Now draw another line from S to W. Guess what? By the methods used in question 3, it's also 8. So SW = 8

TW = TW                        Reflexive

<UTW = STW                 Same reason as in 3. UtW is a right angle

UT = ST                          Given (the marking tells you so.

ΔUTW = ΔSTW              SAS

UW = SW                       Corresponding parts of = triangles are =

SW  = 8

7 0
2 years ago
What is 1/4 as a multiplication sentence
Phoenix [80]
1/4 is the same as 1 * 0.25
3 0
3 years ago
Read 2 more answers
Prove divisibility 45^45·15^15 by 75^30
Anuta_ua [19.1K]

Answer:

3^{75}

Step-by-step explanation:

We are asked to divide our given fraction: \frac{45^{45}*15^{15}}{75^{30}}.

We will simplify our division problem using rules of exponents.

Using product rule of exponents (a*b)^n=a^n*b^n we can write:

45^{45}=(3*15)^{45}=3^{45}*15^{45}

75^{30}=(5*15)^{30}=5^{30}*15^{30}

Substituting these values in our division problem we will get,

\frac{3^{45}*15^{45}*15^{15}}{5^{30}*15^{30}}

Using power rule of exponents a^m*a^n=a^{m+n} we will get,

\frac{3^{45}*15^{45+15}}{5^{30}*15^{30}}

\frac{3^{45}*15^{60}}{5^{30}*15^{30}}

Using quotient rule of exponent \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{3^{45}*15^{60-30}}{5^{30}}

\frac{3^{45}*15^{30}}{5^{30}}

Using product rule of exponents (a*b)^n=a^n*b^n we will get,

\frac{3^{45}*(3*5)^{30}}{5^{30}}

\frac{3^{45}*3^{30}*5^{30}}{5^{30}}

Upon canceling out 5^{30} we will get,

3^{45}*3^{30}

Using power rule of exponents a^m*a^n=a^{m+n} we will get,

3^{45+30}

3^{75}

Therefore, our resulting quotient will be 3^{75}.

8 0
3 years ago
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