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bearhunter [10]
2 years ago
11

5. Consider the system of equation:

Mathematics
2 answers:
liubo4ka [24]2 years ago
7 0

Answer: A

Step-by-step explanation:

goldfiish [28.3K]2 years ago
3 0

Answer:
A

Step-by-step explanation:

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gogolik [260]
6 pints: 17 pints
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*Will mark Brainliest (10 points)*<br><br> Please explain, thanks!
MAVERICK [17]
Standard form Ax + By = C
so
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y + 7 = -1/5(x - 5)
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answer
d. x + 5y = -30
5 0
3 years ago
Determine the equations of the vertical and horizontal asymptotes, if any, for g(x)=x-2/x^2+4x+3
KatRina [158]

Answer:

<h2>B. x = -1, x = -3, y = 0</h2>

Step-by-step explanation:

g(x)=\dfrac{x-2}{x^2+4x+3}\\\\vertical\ asymptote:\\\\x^2+4x+3=0\\x^2+x+3x+3=0\\x(x+1)+3(x+1)=0\\(x+1)(x+3)=0\iff x+1=0\ \vee\ x+3=0\\\\\boxed{x=-1\ \vee\ x=-3}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x-2}{x^2+4x+3}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(\frac{1}{x}-\frac{2}{x^2}\right)}{x^2\left(1+\frac{4}{x}+\frac{3}{x^2}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{\frac{1}{x}-\frac{2}{x^2}}{1+\frac{4}{x}+\frac{3}{x^2}}=\dfrac{0}{1}=0\\\\\boxed{y=0}

4 0
3 years ago
Um...help please??????
Ket [755]

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Step-by-step explanation:

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7 0
2 years ago
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9

Step-by-step explanation:

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3 years ago
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