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Inessa [10]
2 years ago
8

Can someone look at the pic at tell me if Im doing this correctly? I got x=14 ty

Mathematics
1 answer:
Charra [1.4K]2 years ago
7 0

Answer:

x = 14

Step-by-step explanation:

→ Set up an equation

4x + 15 + 39 = 110

→ Simplify

4x + 54 = 110

→ Minus 54 from both sides

4x = 56

→ Divide both sides by 3

x = 14

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Rudiy27
It is 9 degrees because at 6am the temperature was -12 degrees and at 10am the temperature was -3 degrees.
7 0
3 years ago
Hi!
solniwko [45]

Answer:

y = 1x - 4

Step-by-step explanation:

You have to solve for the x intercept on the equation

2x-5y=8\\2x-5(0)=8\\2x=8\\x=4\\(4,0)

That is the x intercept for that equation.

Then solve for the y intercept on the equation

4x-3y=12\\4(0)-3y=12\\-3y=12\\y=-4\\(0,-4)

That is the x intercept for that equation.

Use that to find slope for point slope form

\frac{y_{2}-y_{1}}{x_{2}-_{1}} \\\\\frac{-4-0}{0-4} \\\\\frac{-4}{-4} \\\\1

1 is the slope

and slope makes B the y intercept so the equation is

y = 1x - 4

8 0
3 years ago
Can someone help me ?
V125BC [204]
10/3 x 5 + 10/3 x 1/4
5 0
3 years ago
Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂=  ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for  π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

5 0
3 years ago
The zeros of the function f(x)=(x+2)^2 - 25 are?
zloy xaker [14]
<u>Zeros of the function</u>
f(x) = (x + 2)² - 25
f(x) = (x + 2)(x + 2) - 25
f(x) = x(x + 2) + 2(x + 2) - 25
f(x) = x(x) + x(2) + 2(x) + 2(2) - 25
f(x) = x² + 2x + 2x + 4 - 25
f(x) = x² + 4x + 4 - 25
f(x) = x² + 4x - 21
x² + 4x - 21 = 0
x = <u>-(4) +/- √((4)² - 4(1)(-21))</u>
                      2(1)
x = <u>-4 +/- √(16 + 84)</u>
                   2
x = <u>-4 +/- √(100)
</u>               2<u>
</u>x = <u>-4 +/- 10
</u>            2<u>
</u>x = -2 <u>+</u> 5<u>
</u>x = -2 + 5    x = -2 - 5
x = 3           x = -7
f(x) = x² + 4x - 21
f(3) = (3)² + 4(3) - 21
f(3) = 9 + 12 - 21
f(3) = 21 - 21
f(3) = 0
(x, f(x)) = (3, 0)
or
f(x) = x² + 4x - 21
f(-7) = (-7)² + 4(-7) - 21
f(-7) = 49 - 28 - 21
f(-7) = 21 - 21
f(-7) = 0
(x, f(x)) = (-7, 0)

<u>Vertex</u>
<u>X - Intercept</u>
<u />-b/2a = -(4)/2(1) = -4/2 = -2

<u>Y - Intercept</u>
y = x² + 4x - 21
y = (-2)² + 4(-2) - 21
y = 4 - 8 - 21
y = -4 - 21
y = -25
(x, y) = (-2, -25)
<u />
5 0
3 years ago
Read 2 more answers
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