The terminal point represented by P(x,y), is the coordinate where a certain point lies. Given is 5pi/4 radians - this will be our angle.
Evaluate the values of x and y using sin θ and cos θ
x = cos (5pi/4)
x = -√2/2
y = sin (5pi/4)
y = -√2/2
Therefore, (x,y) is (-√2/2, -√2/2)
1) Determine the horizontal force, Fx, exerted by the block on Usain
cos(20°) = Fx / F => Fx = F*cos(20) = 1700N*cos(20) = 1597.48 N
2) Determine the Impulse of that force on Usain.
I = F*t = 1597.48N * 0.32s = 511.19 N*s
3) Determine change in momentum of Usain, Δp
Δp = I = 511.19 N*s
4) Find change if velocity
Δp = Δ(mV) = mΔV => ΔV = Δp / m = 511.19 N*s / 86 kg = 5.94 m/s
Given the Usain started from rest, the velocity is ΔV - 0 = 5.94 m/s
Answer: 5.94 m/s
Answer: b= -108
Step-by-step explanation:
-6=b/18
-6=b/2(3)^2
-18(6)=b
-108=b
b= -108
*<u><em>I hope that this makes sense :)</em></u>
Answer:
20.14
Step-by-step explanation:
21.15 - 5%(1.01) = 20.14
Answer:
see below
Step-by-step explanation:
16x^2 − 8x + 1
(4x)^2 -8x +1
Factor
This is a perfect square trinomial
a^2 -2ab +b^2 = (a-b)(a-b)
(4x)^2 -8x +1 = (4x-1) (4x-1)
The area of a square is given by
A = s^2
(4x-1) ^2 = s^2
4x-1 = s
The side length is 4x-1
(81x^2 − 4y^2)
(9x)^2 - (2y)^2
This is the difference of squares
a^2 - b^2 = (a-b) (a+b)
(9x-2) (9x+2)
The area of a rectangle is
A = l*w
(81x^2 − 4y^2) = (9x-2) (9x+2)
The dimensions are (9x-2) (9x+2)
