The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft
<h3>How to maximize area?</h3>
Let the length of the rectangular area be x feet
Let the width of the area = y feet
Area of the rectangle = xy square feet
Or xy = 320 square feet
y = 320/x -----(1)
Cost to fence the three sides = $6 per foot
Therefore cost to fence one length and two width of the rectangular area
= 6(x + 2y)
Similarly cost to fence the fourth side = $13 per foot
So, the cost of the remaining length = 13x
Total cost to fence = 6(x + 2y) + 13x
Cost (C) = 6(x + 2y) + 13x
C = 6x + 12y + 13x
C = 19x + 12y
From equation (1),
C = 19x + 12(320/x)
C' = 19 - 3840/x²
At C' = 0, we have;
19 - 3840/x² = 0
19 = 3840/x²
19x² = 3840
x² = 3840/19
x = √(3840/19)
x = 14.22 ft
y = 320/14.22
y = 22.5 ft
Read more about Maximization of Area at; brainly.com/question/13869651
#SPJ1
220 miles is how much Mrs. Johnson drove. because . . .
2x+x=330
2x is twice the amount of Mr. Johnson which equals Mrs. Johnson.
The plain "x" is how much Mr. Johnson drove.
2x+x= 3x
3x=330- x=110
If 'x' is how much Mr. Johnson drove then we multiply that by two to get 220.
Answer:
-3, -2.4, -2 1/4, -1.5, -1 1/8
Step-by-step explanation:
Hope this helps! Let me know if you have any questions! (also would you mind putting me as brainliest pls?)
Step-by-step explanation:
