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DerKrebs [107]
3 years ago
8

I need help with my math hw lol

Mathematics
2 answers:
Iteru [2.4K]3 years ago
6 0

Answer:

A,B and D are correct
10) The LCM of 6 and 12 is 12

Step-by-step explanation:

For the first question:

  1. 2\frac{1}{2}<2\frac{3}{4} ✅
  2. -1.25<-0.75 is correct as -0.75 is closer to zero meaning it is bigger ✅
  3. 1.75<-1/4 is incorrect as negative numbers are smaller than positive numbers ❎
  4. 1.75>0.5 ✅
  5. 2\frac{1}{2}>2\frac{3}{4} ❎
  6. -1.25>-1/4 is incorrect as they are equal

For the second equation:

Multiples of 6 are:

6,12,18...

Multiples of 12 are:

12,24,36...

So the lowest one in both is 12

RSB [31]3 years ago
6 0
Dang dude that’s a high grade lol
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Mariana [72]

Answer:

i am not sure

Step-by-step explanation

i think 78

3 0
3 years ago
PLZZZZZ NEED HELP!!!!!!
expeople1 [14]
The answer is 10. 

Parallel lines show similar triangles showing us that (2x + 6)/10 = (x+6)/8. Solving this equation for x gives us x = 2. Plugging this into 2x + 6 gives us 2(2) + 6 = 10. 
6 0
3 years ago
A rectangular poster is 1/2 yard long and 3/4 yard tall. john says the area of the poster is 5/4 square yards. What is Johns mis
alina1380 [7]
Answer can't be in improper fraction
5 0
3 years ago
A uniform 41.0 kg scaffold of length 6.6 m is supported by two light cables, as shown below. A 74.0 kg painter stands 1.0 m from
Nimfa-mama [501]

Step-by-step explanation:

Let

m_p = mass of the painter

m_s = mass of the scaffold

m_e = mass of the equipment

T = tension in the cables

In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as

3T = (m_p + m_s + m_e)g\:\:\:\:\:\:\:(1)

Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of m_e. The net torque on the scaffold is then

T(1.4\:\text{m}) + m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m}) - 2T(5.2\:\text{m}) = 0

Solving for T,

9T = m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})

or

T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]

\:\:\:\:= 423.3\:\text{N}

To solve for the the mass of the equipment m_e, use the value for T into Eqn(1):

m_e = \dfrac{3T - (m_p + m_s)g}{g} = 14.6\:\text{kg}

6 0
3 years ago
Help! Please make sure its in standard form. Thanks
kogti [31]

Lets work out each set of brackets individually:

8 x 10 = 80

4 x 1 = 4

For the last bracket, note that: 2 times 1/100  is the same as 2 divided by 100

So:

2 x  1/100 = 2 ÷ 100

               = 0.02

Now add up all of the numbers we worked out:

80 + 4 + 0.02 = 84 + 0.02

                     = 84.02

__________________

Answer:

C. 84.02

3 0
4 years ago
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