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2 years ago

7.) A plane was flying at an altitude of 35,000 feet. It descended 6,000 feet to avoid some

Mathematics

1 answer:

worty [1.4K]2 years ago

4 0

35,000 ft - 6,000 ft = 29,000 ft

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Let X be a Bernoulli rv with pmf as in Example 3.18. a. Compute E(X2 ). b. Show that V(X) 5 p(1 2 p). c. Compute E(X79).

spayn [35]

The Bernoulli distribution is a distribution whose random variable can only take 0 or 1

The value of E(x2) is p
The value of V(x) is p(1 - p)
The value of E(x79) is p

<h3>How to compute E(x2)</h3>

The distribution is given as:

p(0) = 1 - p

p(1) = p

The expected value of x2, E(x2) is calculated as:

$E(x^2) = \sum x^2 * P(x)$

So, we have:

$E(x^2) = 0^2 * (1- p) + 1^2 * p$

Evaluate the exponents

$E(x^2) = 0 * (1- p) + 1 * p$

Multiply

$E(x^2) = 0 +p$

Add

$E(x^2) = p$

Hence, the value of E(x2) is p

<h3>How to compute V(x)</h3>

This is calculated as:

$V(x) = E(x^2) - (E(x))^2$

Start by calculating E(x) using:

$E(x) = \sum x * P(x)$

So, we have:

$E(x) = 0 * (1- p) + 1 * p$

$E(x) = p$

Recall that:

$V(x) = E(x^2) - (E(x))^2$

So, we have:

$V(x) = p - p^2$

Factor out p

$V(x) = p(1 - p)$

Hence, the value of V(x) is p(1 - p)

<h3>How to compute E(x79)</h3>

The expected value of x79, E(x79) is calculated as:

$E(x^{79}) = \sum x^{79} * P(x)$

So, we have:

$E(x^{79}) = 0^{79} * (1- p) + 1^{79} * p$

Evaluate the exponents

$E(x^{79}) = 0 * (1- p) + 1 * p$

Multiply

$E(x^{79}) = 0 + p$

Add

$E(x^{79}) = p$

Hence, the value of E(x79) is p

Read more about probability distribution at:

brainly.com/question/15246027

5 0

2 years ago

Find the distance between the points (<br> –<br> 18,4) and (<br> –<br> 18,<br> –<br> 20).

worty [1.4K]

Answer:

(-18,4) is 16 units below (-18,20). hope this helps

Step-by-step explanation:

- Zombie

6 0

2 years ago

The sum of three numbers is 10. The first number minus the second number plus the third is 6. The first minus the third is 2 mor

GenaCL600 [577]

So the answer is 6,0,4.

3 0

3 years ago

Write 68,127,000,000,000,000 in scientific notation. (x10^

Alexeev081 [22]

Answer:

6.8127 × 10^16

Step-by-step explanation:

Hope this helps:)

7 0

2 years ago

Read 2 more answers

How do I find the arc length with given radius & central angel?

ella [17]

The length of an arc subtended by a central angle is proportional to the circle's circumference. If the given central angle has measure $\theta$ and the circle has radius $r$ , then the arc has length $\ell$ such that

$\dfrac{\ell}\theta=\dfrac{2\pi r}{2\pi}=r$

where $\theta$ is given in radians. Then

$\ell=r\theta$

If $\theta$ is given in degrees, then

$\dfrac{\ell}\theta=\dfrac{2\pi r}{360}\implies\ell=\dfrac{\theta\pi r}{180}$

8 0

2 years ago