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romanna [79]
3 years ago
10

The area of a rectangular field is 5695 m².

Mathematics
1 answer:
denpristay [2]3 years ago
3 0

Answer:

85 m

Step-by-step explanation:

5696/67=85

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The person who answers these three questions will get the brianlist
LuckyWell [14K]

Answer:  The answer for 1. is B For 2 its c and for 3 its D

also I LOVE MY HERO ACEDAMEIA

Step-by-step explanation:

8 0
4 years ago
A. Use composition to prove whether or not the functions are inverses of each other.
kogti [31]

A. In a composition of two functions the first function is evaluated, and then the second function is evaluated on the result of the first function. In other word, you are going to evaluate the second function in the first function.

Remember that you can evaluate function at any number just replacing the variable in the function with the number. For example, let's evaluate our function f(x) at x=1:

f(x)=\frac{1}{x-3}

f(1)=\frac{1}{1-3}

f(1)=\frac{1}{-2}

Similarly, to find the composition of f(x) andg(x), we are going to evaluate f(x) at g(x). In other words, we are going to replace x in f(x) with \frac{3x+1}{x}:

f(x)=\frac{1}{x-3}

f(g(x) = f(\frac{3x+1}{x} ) = \frac{1}{\frac{3x+1}{x} -3}

Remember that two functions are inverse if after simplifying their composition, we end up with just x. Let's simplify and see what happens.

f(g(x)=\frac{1}{\frac{3x+1}{x} -3}

f(g(x)=\frac{1}{\frac{3x+1-3x}{x} }

f(g(x)=\frac{1}{\frac{1}{x} }

f(g(x)=x

Now let's do the same for g(f(x)):

g(\frac{1}{x-3} )=\frac{3(\frac{1}{x-3})+1}{x}

g(\frac{1}{x-3} )=\frac{\frac{3}{x-3}+1}{x}

g(\frac{1}{x-3} )=\frac{\frac{3+x-3}{x-3}}{x}

g(\frac{1}{x-3} )=\frac{\frac{x}{x-3}}{x}

g(\frac{1}{x-3} )=\frac{x}{x(x-3)}

g(f(x))=\frac{x}{x(x-3)}

We can conclude that g(x) is the inverse function of f(x), but f(x) is not the inverse function of g(x).

B. The domain of a function is the set of all the possible values the independent variable can have. In other words, the domain are all the possible x-values of function.

Now, interval notation is a way to represent and interval using an ordered pair of numbers called the end points; we use brackets [ ] to indicate that the end points are included in the interval and parenthesis ( ) to indicate that they are excluded.

Notice that when x=0, g(x)=\frac{3(0)+1}{0} =\frac{0}{0}, so when x=0, g(x) is not defined; therefore we have to exclude zero from the domain of f(g(x)).

We can conclude that the domain of the composite function f(g(x)) in interval notation is (-∞,0)U(0,∞)

Now let's do the same for g(f(x)).

Notice that the composition is not defined when its denominator equals zero, so we are going to set its denominator equal to zero to find the values we should exclude from its domain:

x(x-3)=0

x=0 and x-3=0

x=0 and x=3

Know we know that we need to exclude x=0 and x=3 from the domain of g(f(x)).

We can conclude that the domain of the composition function g(f(x)) is (-∞,0)U(0,3)U(3,∞)

4 0
3 years ago
Read 2 more answers
No links please, question is in photo,
Natasha_Volkova [10]

Answer:

C

Step-by-step explanation:

Two like therms have the same literal part, in case we have two terms:

6y^3z and 8y^3z

4 0
3 years ago
Complete. Y squared plus 15 multiplied by y plus 56 equals the quantity y plus 7 end of quantity multiplied by what expression.
Eduardwww [97]
Hello,


The answer is D, y-7


Hope this helps
8 0
4 years ago
Read 2 more answers
Help me solve the problem! Please help
Sav [38]

Answer:

m+n=140

Step-by-step explanation:

So the angles in a triangle always add up to 180. We already know that the first angle in the triangle is 40 degrees because it's shown in the angle below the triangle. So we have 140 degrees left since 40 is taken up. That eans m+n=140

6 0
3 years ago
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