Answer:
Null hypothesis:
B) H0: μ1 = μ2 = μ3 = μ4
Alternate hypothesis:
A) H1: At least one mean is different.
Reject H0 if F>2.74
H0 is rejected
Step-by-step explanation:
Null hypothesis always contain equality so, null hypothesis would be
B) H0: μ1 = μ2 = μ3 = μ4.
Alternate hypothesis doesn't contain equality so, alternate hypothesis would be
A) H1: At least one mean is different.
Decision rule will be "reject null hypothesis if calculated F is greater than critical value of F".
Critical value of F is F0.05(3,68)=2.74.
So, decision rule will be Reject H0 if F>2.74.
As, calculated F 2.77 is greater than 2.74 so, we reject our null hypothesis and conclude that there is sufficient evidence to suggests a difference in the means for the different types of mail at 5% level of significance.
Answer:
-152
Step-by-step explanation:
-152 < 12
-152 is negative, which means it is less than 1.
12 is positive, which means it is greater than 1.
Therefore, -152 is the lesser of the two given numbers.
Have a great rest of your day! :)
Answer is D. x^2 > 4 (on number line, 2 is open)
With this problem, you should first look at the equation for the area of a trapezoid. That is A = (1/2)(B1 + B2)*H. We know what A, B1, and B2 are so you just need to solve for height. So, based on the equation:
![3x^{3} -16 x^{2} + 31x-20 = (1/2)(x+5+ x^{2} -5x)*h](https://tex.z-dn.net/?f=%203x%5E%7B3%7D%20-16%20x%5E%7B2%7D%20%2B%2031x-20%20%3D%20%281%2F2%29%28x%2B5%2B%20x%5E%7B2%7D%20-5x%29%2Ah)
Next, you would have:
![6x^{3} -32x^{2} +62x-40=(x^{2}-4x+5)*h](https://tex.z-dn.net/?f=6x%5E%7B3%7D%20-32x%5E%7B2%7D%20%2B62x-40%3D%28x%5E%7B2%7D-4x%2B5%29%2Ah%20)
Next solve for h by dividing the polynomials like so:
![h = (6 x^{3}-32 x^{2} +62x-40)/( x^{2} -4x+5)](https://tex.z-dn.net/?f=h%20%3D%20%286%20x%5E%7B3%7D-32%20x%5E%7B2%7D%20%2B62x-40%29%2F%28%20x%5E%7B2%7D%20-4x%2B5%29%20)
Using long division you get:
Step-by-step explanation:
what i understand is x is a axis