
We know that, in ∆ABC,
∠A+∠B+∠C = 180°
But the triangle is right angled at C
ie., ∠C = 90°
Therefore, ∠A+∠B+ 90° = 180°
⇒ ∠A + ∠B = 90°
Therefore, <u>cos(A + B) = cos 90º = 0</u>
Answer:
The answer is 6 units! Have a nice day! :D
Step-by-step explanation:
17.89, is this an option?
25 add them up Your welcome
Y=x-v\b
if that's all your information then that's the answer