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Ipatiy [6.2K]
2 years ago
11

Please help me, i promise its worth it!!!

Mathematics
2 answers:
Eva8 [605]2 years ago
7 0

Step-by-step explanation:

Given,

Length= 4/3 x

Breadth= x

Perimeter=2(l+b)

55=2(4x/3+x)

55=8x/3+2x

55=(8x+6x)/3

55=14x/3

55×3=14x

165=14x

165/14=x

x=11.78

Hence,

Breadth=x=11.78

Length=4x/3=(4×11.78)/3=15.7067

Rashid [163]2 years ago
5 0

\\ \sf\longmapsto 2(L+B)=55

\\ \sf\longmapsto 2(\dfrac{4}{3}x+x)=55

\\ \sf\longmapsto \dfrac{8}{3}x+2x=55

\\ \sf\longmapsto \dfrac{8x+6x}{3}=55

\\ \sf\longmapsto \dfrac{14x}{3}=55

\\ \sf\longmapsto 14x=165

\\ \sf\longmapsto x=11.78

\\ \sf\longmapsto x\approx 12

Now

  • B=x=12
  • L=4/3(12)=4(4)=16
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Answer:

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lara [203]

Answer:

The vertices of triangle A'B'C' produced by (x, y)  →  (x+5, y-2)  will be:

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Step-by-step explanation:

Given the vertices of an original triangle ΔABC such that

  • A = (3, 0)
  • B = (3, 2)
  • C = (0, -3)

As the rule of translation is given by

Translation: (x, y)  →  (x+5, y-2)

So, after the translation the vertices of the original triangle ΔABC will be translated as:

A = (3, 0)  → (x+5, y-2)  ⇒ (3+5, 0-2) = A'(8, -2)

B = (3, 2)  →  (x+5, y-2)  ⇒ (3+5, 2-2) = B'(8, 0)

C = (0, -3) → (x+5, y-2)  ⇒ (0+5, -3-2) = C'(5, -5)

Therefore, the vertices of triangle A'B'C' produced by (x, y)  →  (x+5, y-2)  will be:

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