7.9 millimeters (0.705 inch) in diameter. So yes it is.
X^2+4x+4+12x+24-14=0
x^2+16x+14=0
x= -16 ± √(16)^2-4(1)(14) /2(1)
=-16± √200 /2
-16 ± 2√50 /2
-16 ± 10√2 /2
-8 ± 5√2
Answer:
16/33
Step-by-step explanation:
12C4(total possible outcomes)=495
Since there are 6 married couples there must be 6*[2C2×10C2]=270
must subtracted 15 since when there are 2 couples in a group would have doubled 270-15=255
the no of groupings with no married couples 495-255 =240
probability=no of favourable outcomes /no of possible outcome
probability=240/495= 16/33
