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3 years ago

What angle is an x–intercept for the function y= cos(.5x)

1 answer:

5 0

X-intercept appears at when y = 0

So when cos(0.5x) = 0 -> 0.5x = pi/2 + n*pi, where n is any random integers

So x = pi + 2npi, so the angle can be pi, 3pi, 5pi, so on

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Oliver saves pennies and he saves the same number of pennies each week. His father gave him a jar of pennies to get him started.

Elodia [21]

Answer:b 150+40

Step-by-step explanation: i add 150+40 = 190 than i multiply 40 times the week so 13 and is 520 and than add 150 so its 670. :) your welcome

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2 years ago

What formula is used to find the rate of change

Yuliya22 [10]

Answer:

Average rate of change uses the slope formula (AKA rise over run AKA change in y over change in x AKA y2-y1 over x2-x1). To find y2 and y1, plug the x-values from your interval end points into the function f(x). Say f(1) and f(a). i really hope that helps

Step-by-step explanation:

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3 years ago

Help in Circumference of a circle A small pizza has a diameter of 21 cm.

Novay_Z [31]

The circumference of any circle is (pi) x (the diameter of the circle).

The problem gives you both numbers, so all you have to do is multiply them.

Circumference = (pi) x (diameter) = (3.14) x (21cm) = <em>65.94 cm .</em>

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3 years ago

If f(x) = - 3x - 3. g(x) = 2x2 + 6x - 5. and h(x) = - 8x2 + 6. find f(-3). I REALLY NEED THIS

shepuryov [24]

Answer:

f(-3) = 6

Step-by-step explanation:

input -3 in f(x)

so f(-3) = -3(-3) - 3

multiple and add

f(-3) = 6

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3 years ago

Find the domain of the function y = 3 tan(23x)

solmaris [256]

Answer:

$\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

In other words, the $x$ in $f(x) = 3\, \tan(23\, x)$ could be any real number as long as $x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)$ for all integer $k$ (including negative integers.)

Step-by-step explanation:

The tangent function $y = \tan(x)$ has a real value for real inputs $x$ as long as the input $x \ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

Hence, the domain of the original tangent function is $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

On the other hand, in the function $f(x) = 3\, \tan(23\, x)$ , the input to the tangent function is replaced with $(23\, x)$ .

The transformed tangent function $\tan(23\, x)$ would have a real value as long as its input $(23\, x)$ ensures that $23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

In other words, $\tan(23\, x)$ would have a real value as long as $x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right)$ .

Accordingly, the domain of $f(x) = 3\, \tan(23\, x)$ would be $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

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2 years ago