Answer:
= 11/3
Step-by-step explanation:
1. COMBINE MULTIPLIED TERMS INTO A SINGLE FRACTION
- 7/3 (3x-2)= -21
-7 (3x-2) = -21
-----------------------
3
2. DISTRIBUTE
-7( 3x- 2) ➗ 3 =-21
3. MULTIPLY ALL TERMS BY THE SAME VALUE TO ELIMINATE FRACTION DENOMINATORS
-21x + 14 ➗ 3 = 3 (-21)
4. CANCEL MULTIPLIED TERMS THAT ARE IN THE DENOMINATOR
3 ( -21x + 14) ➗ 3 (-21)
5. MULIPLY THE NUMBERS
-21x + 14 = 3(-21)
6. SUBTRACT 14 FROM BOTH SIDES OF THE EQUATION
-21x + 14 = -63
7. SIMPLIFY
-21x = - 77
8. DIVIDE BOTH SIDES OF THE EQUATION BY THE SAME TERM
-21x/-21 = -77/-21
9. SIMPLIFY
x = 11/3
Answer:5m/2
Step-by-step explanation:
3m-m/2
(2×3m-1×m)/2
(6m-m)/2=5m/2
The set of x ordinates or {1,2,3}
Answer: Test statistic = -8 and rejected region is (-∞,-1.966) and (1.966, ∞)
Step-by-step explanation:
Since we have given that
X is the length of a rod.
Sample Mean = 2 inches
Standard deviation = 0.5 inches
n = 400
Hypothesis are
Test statistics would be
Degrees of freedom = n-1 =400-1 =39
and 
Using the t-distribution table, we get that critical value z = 1.966
Since the two tail test will be applied to this,
So, the acceptance region will be (-1.966, 1.966)
Hence, the rejected region will be (-∞,-1.966) and (1.966, ∞)
Answer:
The answer to your question is 1.875 gallons
Step-by-step explanation:
Data
distance = 50 mi
volume of gas = 1 gal
volume for 150 km = ?
Process
1.- Convert 50 mi into kilometers
1 mile ------------------- 1.6 km
x ------------------ 150 km
x = (150 x 1)/1.6
x = 93.75 mi
2.- Calculate the gallons wasted
1 gallon ----------------- 50 mi
x ---------------- 93.75 mi
x = (93.75 x 1)/50
x = 93.75/50
x = 1.875 gallons
