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Afina-wow [57]
3 years ago
9

The mode, the range and the mean of the following set of data are, respectively

Mathematics
1 answer:
alina1380 [7]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

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Find the quotient. 2 1/3 ÷ 1 <br><br> help
Jet001 [13]

Answer:

2 \frac{1}{3}  \div 1 \frac{1}{3}  \\ = \frac{7}{3}  \div  \frac{4}{3}  \\ = \frac{7}{3}  \times  \frac{3}{4}  \\  =  \frac{7}{4}

<h3><u>PLEASE MARK ME BRAINLIEST</u></h3>
4 0
3 years ago
​ A sample of n = 9 college students is used to evaluate the effectiveness of a new Study Skills Workshop. Each student’s grade
forsale [732]

Answer:

B) μD = 0.60 ± 0.10(1.397)

Step-by-step explanation:

The confidence interval is given by:

MD±t_{\alpha/2, n-1} \frac{s}{\sqrt{n} }

Where

MD=60

n=9

df=n-1=8

t_{\alpha/2, n-1}=1.397

s=\sqrt{0.09} =0.3

Then the confidence interval is

μD=0.60±1.397*(0.3/√9)

μD=0.60±0.10*(1.397)

6 0
3 years ago
Here is a diagram and its corresponding equation. Find the solution to the equation.
Katen [24]
4(x + 7) = 38

Since there is no operation sign between the 4 and parenthesis, it makes it an automatic multiplication problem.

You would use distributive property to multiply each which should leave your equation looking like this afterwards:

4x + 28 = 38
(4 times x and 4 times 7)

You would then solve it like a two step equation,

1. +28 - 28 = 0
2. 38 - 28 = 10

4x = 10

10 divided by 4 = 2.5

x = 2.5

We can recheck our work by substituting in the value of x.

4(2.5 + 7) = 38

10 + 28 = 38

When we substituted in the value, it gave us the correct inequality.

Therefore,
x = 2.5
5 0
2 years ago
Read 2 more answers
H(x)=x-1 is a factor of f(x)=x^5+1. Please select the best answer from the choices provided.
Zanzabum

Answer:true

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the area of a cross section that is parallel to face CDHG ?
Dennis_Churaev [7]

Answer: Area of cross section that is parallel to face CDHG is 432 cm².

Step-by-step explanation:

Since we have given that

There is a cross section that is parallel to face CDHG.

So, Length of cross section would be 36 cm

Width of cross section would be 12 cm.

So, Area of cross section would be

Length\times breadth\\\\=36\times 12\\\\=432\ cm^2

Hence, Area of cross section that is parallel to face CDHG is 432 cm².

8 0
3 years ago
Read 2 more answers
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