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choli [55]
3 years ago
15

Compound interest will always be lower than simple interest. True False

Mathematics
1 answer:
matrenka [14]3 years ago
6 0

Step-by-step explanation:

True (assuming that the time is long enough to have interest calculated upon interest -- more than one period of time).

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The sum of two numbers is 34. The smaller number is 6 less than the larger
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16 and 22 are ur numbers
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1 1/3 TIMES 2 3/4 = <br> ANSWER ASAPPPP<br> EXPLAIN STEP BY STEP
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1/2

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Divide. Round your answer to the nearest hundredth.<br> 4,266.98 divide 3
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A sphere has a volume of 1,436. 03m3, what is the approximate length of its radius?.
makkiz [27]

The sphere with the volume 1436.03 m³ has 7m long radius.

To find out the approximate length of its radius by using the formula to calculate volume of sphere is:

V= 4πr³/3

The value of π is 22/7 or 3.14.

So, V = 4 × 3.14 × r³ / 3

Volume of the sphere is given which is 1436.03 m³.

Thus, r³ = 1436.03×3 / 4×3.14

r = ³√ 4308.09/12.56 = ³√343 = 7 m.

Hence, the radius of the given sphere is 7 m.

The cube root of a number is the factor that we multiply by itself three times to get that number.

For example, the cube root of 27 is 3.

To learn more about the sphere click here brainly.com/question/19868745

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3 0
2 years ago
Which statement is true?
Ray Of Light [21]

We will see that the fourth statement:

"-0.3*|3 + 8x| = 0.9 has no solutions."

Is the true statement.

<h3>Which statement is true?</h3>

Here we need to see which statement regarding absolute value equations is true.

Here you can see that the fourth statement is:

-0.3*|3 + 8x| = 0.9   has no solutions.

Now, if you look at the left side of the above equation, the left side will always be negative, while the right side is positive, then the equation can't have a solution.

There is no value of x that makes that equation true, so it is true that the given equation has no solutions. This is the correct statement.

If you want to learn more about absolute values, you can read:

brainly.com/question/1782403

5 0
3 years ago
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