<span>The higher the sum of the numbers 24 407 and 14 509 towards their difference?</span>
Answer:
You know if it is day time or night time
Step-by-step explanation:
first subtract the last equation from the first. this gives:-
-x + y = -8 .....................(1)
Then multiply the first equation by 2 and add it to the 2nd equations This gives
9x = 18
so x = 2
and from equation (1) y = -8 + 2 = -6
Substituting for x and y in the second equation
z = (24 -5(2) -12) / 2 = 1
Answer is choice b.
Answer:
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
There will be $5636.359 in the account after 3 years if the interest is compounded monthly
Step-by-step explanation:
Tamira invests $5,000 in an account
Rate of interest = 4%
Time = 3 years
Case 1:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 1
Formula :![A=P(1+r)^t](https://tex.z-dn.net/?f=A%3DP%281%2Br%29%5Et)
![A=5000(1+0.04)^3](https://tex.z-dn.net/?f=A%3D5000%281%2B0.04%29%5E3)
A=5624.32
There will be $5624.32 in the account after 3 years if the interest is compounded annually.
Case 2:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 2
Formula : ![A=P(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
![A=5000(1+\frac{0.04}{2})^{2 \times 3}](https://tex.z-dn.net/?f=A%3D5000%281%2B%5Cfrac%7B0.04%7D%7B2%7D%29%5E%7B2%20%5Ctimes%203%7D)
A=5630.812
There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.
Case 3:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula : ![A=P(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
![A=5000(1+\frac{0.04}{4})^{4 \times 3}](https://tex.z-dn.net/?f=A%3D5000%281%2B%5Cfrac%7B0.04%7D%7B4%7D%29%5E%7B4%20%5Ctimes%203%7D)
A=5634.125
There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.
Case 4:
Principal = 5000
Rate of interest = 4%
Time = 3 years
No. of compounds per year = 4
Formula :![A=P(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
![A=5000(1+\frac{0.04}{12})^{12 \times 3}](https://tex.z-dn.net/?f=A%3D5000%281%2B%5Cfrac%7B0.04%7D%7B12%7D%29%5E%7B12%20%5Ctimes%203%7D)
A=5636.359
There will be $5636.359 in the account after 3 years if the interest is compounded monthly