Hello!
To find the line parallel to the line x + 2y = 6 and passing through the point (1, -6), we will need to know that if two lines are parallel, then their slopes are equivalent to each other.
Since the given equation is written in standard form, we will need to change it to slope-intercept form to get the slope. Slope-intercept form is: y = mx + b.
x + 2y = 6 (subtract x from both sides)
2y = 6 - x (divide both sides by 2)
y = 6/2 - x/2
y = -1/2x + 3 | The slope of parallel lines are -1/2.
Since we are given the slope, we need to find the y-intercept of the line that goes through the point (1, -6) by substituting that point into a new equation with a slope of m equalling to -1/2.
y = -1/2x + b (substitute the given point)
-6 = -1/2(1) + b (simplify - multiply)
-6 = -1/2 + b (add 1/2 to both sides)
b = -11/2 | The y-intercept of the parallel line is -13/2.
Therefore, the line parallel to x + 2y = 6 and goes through the ordered pair (1, -6) is y = -1/2x + -11/2.
Answer:
x= -2
Step-by-step explanation:
4x+4=-3x-10
7x+4=-10
7x=-14
x=-2
Answer: 240
Step-by-step explanation:198+48
Answer:
The solution is similar to the 2-point form of the equation for a line:
y = (y2 -y1)/(x2 -x1)·x + (y1) -(x1)(y2 -y1)/(x2 -x1)
Step-by-step explanation:
Using the two points, write two equations in the unknowns of the equation of the line.
For example, you can use the equation ...
y = mx + b
Then for the points (x1, y1) and (x2, y2) you have two equations in m and b:
b + (x1)m = (y1)
b + (x2)m = (y2)
The corresponding augmented matrix for this system is ...
![\left[\begin{array}{cc|c}1&x1&y1\\1&x2&y2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26x1%26y1%5C%5C1%26x2%26y2%5Cend%7Barray%7D%5Cright%5D)
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The "b" variable can be eliminated by subtracting the first equation from the second. This puts a 0 in row 2 column 1 of the matrix, per <em>Gaussian Elimination</em>.
0 + (x2 -x1)m = (y2 -y1)
Dividing by the value in row 2 column 2 gives you the value of m:
m = (y2 -y1)/(x2 -x1)
This value can be substituted into either equation to find the value of b.
b = (y1) -(x1)(y2 -y1)/(x2 -x1) . . . . . substituting for m in the first equation