Y = -2(x + 3)^2 - 4
First expand the parentheses:-
y = -2(x + 3)(x + 3) - 4
y = -2 [(x(x + 3) + 3(x + 3)] - 4
y = -2 ( x^2 + 3x + 3x + 9) - 4
y = -2(x^2 + 6x + 9) - 4
Now distribute the -2 over the parentheses:-
y = -2x^2 - 12x - 18 - 4
y = -2x^2 - 12x - 22 Answer
Answer:
No clue, sorry, I need points
Radius of the circle = sqrt((7 - 0)^2 + (0 - 0)^2) = sqrt(7^2) = 7
Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the centre of the circle.
Required equation = (x - 0)^2 + (y - 0)^2 = 7^2
x^2 + y^2 = 49
Answer:
-17 = x/-3 for x.
Step-by-step explanation:
Let us check the transformations. The first step is regarding the argument of the function, the -2x part. So, first of all, the minus sign implies that the function is reflected along the y-axis since f(x) is replaced with f(-x). However, cosx is symmetric along that axis so there is no change on the graph. Also, the 2 factor means that the function is compressed along the x-axis, since now f(2) corresponds to f(1) etc. (if we substitute 1 in the cos(2x), it is as if substituting 2 in the origninal function cosx). Finally, we have that the factor 3 in front of cos, implies that the function is dilated along the y-axis; the highs become 3 times higher and the lows 3 times low.
