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Gnom [1K]
2 years ago
9

Find the value of x in isosceles trapezoid ABCD Given AC=3x-16 and BD=10x-86

Mathematics
1 answer:
Nastasia [14]2 years ago
7 0
X = 10
(WORK SHOWN BELOW)

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What does 52/100=?/387.50 equal?
anzhelika [568]

Answer:

Step-by-step explanation:

4 0
3 years ago
10 pts
VLD [36.1K]
I think the answer is 3/5
6 0
3 years ago
I need help with 11 and 12
Yakvenalex [24]

Answer:

Both are inverse pairs  

Step-by-step explanation:

Question 11

g(x)= 4 + \dfrac{8}{5}x

(a) Rename g(x) as y  

y = 4 + \dfrac{8}{5}x

(b) Solve for x :  

\dfrac{8}{5}x = y - 4

(c) Multiply each side by ⅝

x = \dfrac{5}{8}(y - 4) = \dfrac{5}{8}y - \dfrac{5}{2}

(d) Switch x and y  

y = \dfrac{5}{8}x - \dfrac{5}{2}

(e) Rename y as the inverse function  

g^{-1}(x) = \dfrac{5}{8}x - \dfrac{5}{2}

(f) Compare with your function

f(x) = \dfrac{5}{8}x - \dfrac{5}{2}\\\\f(x) = g^{-1}(x)

f(x) and g(x) are inverse functions.

The graphs of inverse functions are reflections of each other across the line y = x.

In the first diagram, the graph of ƒ(x) (blue) is the reflection of g(x) (red) about the line y = x (black)

 

Question 12

h(x)= x - 2

(a) Rename h(x) as y  

y = x - 2

(b) Solve for x:  

x = y + 2

(c) Switch x and y  

y  = x + 2

(e) Rename y as the inverse function  

h⁻¹(x) = x + 2

(f) Compare with your function

f(x) = x + 2

f(x) = h⁻¹(x)

h(x) and ƒ(x) are inverse functions.

The graph of h(x) (blue) reflects ƒ(x) (red) across the line y = x (black).

5 0
3 years ago
Simplify. (12)2−6(2−23) Enter your answer, as a simplified fraction, in the box.
katen-ka-za [31]

Answer: 240

Step-by-step explanation:

Distribute all numbers

24 - 6(-21)

24 - (-126)

24+216

240

8 0
3 years ago
Lol please help im bad at maths ;n;
aivan3 [116]

Answer:

60

Step-by-step explanation:

You want to then multiply 5*4*3 to represent the different combinations we can make for each place. This gives us a total of 60 different possible ways that the runners can come in 1st, 2nd, and 3rd place, assuming no ties.

8 0
2 years ago
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