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kozerog [31]
2 years ago
14

What is $25 at 14% off

Mathematics
2 answers:
Gala2k [10]2 years ago
8 0

Answer:

$21.50

Step-by-step explanation:

10% of $25 is $2.50

4% of $25 is (1% of 25)×4

4% of $25 = $0.25×4

4%=$1

10%+4%=14%

$2.50+$1=14%

$3.50=14%

$25-$3.50=£21.50

Gelneren [198K]2 years ago
6 0
Answer: $21.50

25 x 0.14 = 3.5
25 - 3.5 = 21.50

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The sum of the first and third of three consecutive integers is 140. find the three even integers​
Elina [12.6K]

Answer:

It would be 68,70,72

Step-by-step explanation:

The sum of first and third of 3 consecutive number is 140 as 68+72 is 140.

68 is the first

72 is the third

They are all even numbers as well

6 0
3 years ago
In a bean bag toss game players earn 2 points for each beanbag that lands on the game board and 5 points for each bean bag that
miskamm [114]

Answer:

It is 2+2

Step-by-step explanation:

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A family has an annual income of ​$25,200. of​ this, 1/4 is spent for​ food, 1/5 for​ housing, 1/10 for​ clothing, 1/9 for​ savi
Firlakuza [10]
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8 0
3 years ago
Find the values of λ for which the determinant is zero.
elena55 [62]

Answer:

Determinant are special number that can only be defined for square matrices.

Step-by-step explanation:

Determinant are particularly important for analysis. The inverse of a matrix exist, if the determinant is not equal to zero.

How to find determinant

For a 2×2 matrix

det ( \left[\begin{array}{cc}x&y\\a&z\end{array}\right] ) = xz-ay

For a 3×3 matrix

we first decompose it to 2×2

det (\left[\begin{array}{ccc}k&l&m\\o&p&q\\r&s&t\end{array}\right] )\\\\= k*det(\left[\begin{array}{cc}p&q\\s&t\end{array}\right] ) - l*det(\left[\begin{array}{cc}o&q\\r&t\end{array}\right] ) + m*det(\left[\begin{array}{cc}o&p\\r&s\end{array}\right] ) \\\\=k(pt-sq) - l(ot-rq) + m(os-rp)

Example

Find the values of λ for which the determinant is zero

\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right]

det(\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right])\\\\= s*det(\left[\begin{array}{cc}s&-1\\-1&1\end{array}\right] ) - (-1)*det(\left[\begin{array}{cc}-1&-1\\0&1\end{array}\right] ) + 0*det(\left[\begin{array}{cc}-1&s\\0&-1\end{array}\right] )\\\\= s(s(1)-(-1*-1)) - (-1)(-1*1 - (-1*0)) + 0\\= s(s - 1)) + 1(-1 + 0) \\=s^{2} -s-1

Equating the determinant to zero

s^{2} -s-1 =0\\

s = \frac{1}{2} * (1 ±5 )

s = 1.61 or -0.61

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Let x represent the number of television show episodes that are taped in a season. enter an expression for the number of episode
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2x, I suppose, 2 times x
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