Answer:
![x=-7](https://tex.z-dn.net/?f=x%3D-7)
Step-by-step explanation:
We have been given an equation
. We are asked to find the zeros of equation by factoring and then find the line of symmetry of the parabola.
Let us factor our given equation as:
![2x^2+28x+96=0](https://tex.z-dn.net/?f=2x%5E2%2B28x%2B96%3D0)
Dividing both sides by 2:
![x^2+14x+48=0](https://tex.z-dn.net/?f=x%5E2%2B14x%2B48%3D0)
Splitting the middle term:
![x^2+6x+8x+48=0](https://tex.z-dn.net/?f=x%5E2%2B6x%2B8x%2B48%3D0)
![(x^2+6x)+(8x+48)=0](https://tex.z-dn.net/?f=%28x%5E2%2B6x%29%2B%288x%2B48%29%3D0)
![x(x+6)+8(x+6)=0](https://tex.z-dn.net/?f=x%28x%2B6%29%2B8%28x%2B6%29%3D0)
![(x+8)(x+6)=0](https://tex.z-dn.net/?f=%28x%2B8%29%28x%2B6%29%3D0)
Using zero product property:
![(x+8)=0\text{ (or) }(x+6)=0](https://tex.z-dn.net/?f=%28x%2B8%29%3D0%5Ctext%7B%20%28or%29%20%7D%28x%2B6%29%3D0)
![x+8=0\text{ (or) }x+6=0](https://tex.z-dn.net/?f=x%2B8%3D0%5Ctext%7B%20%28or%29%20%7Dx%2B6%3D0)
![x=-8\text{ (or) }x=-6](https://tex.z-dn.net/?f=x%3D-8%5Ctext%7B%20%28or%29%20%7Dx%3D-6)
Therefore, the zeros of the given equation are
.
We know that the line of symmetry of a parabola is equal to the x-coordinate of vertex of parabola.
We also know that x-coordinate of vertex of parabola is equal to the average of zeros. So x-coordinate of vertex of parabola would be:
![\frac{-8+(-6)}{2}=\frac{-14}{2}=-7](https://tex.z-dn.net/?f=%5Cfrac%7B-8%2B%28-6%29%7D%7B2%7D%3D%5Cfrac%7B-14%7D%7B2%7D%3D-7)
Therefore, the equation
represents the line of symmetry of the given parabola.
Answer:
About 5.5, but it is technically closer to 5.6 so I am not entirely sure
Step-by-step explanation:
Since EB and DC are parallel, triangles ABE and ACD are similar by AA. Therefore:
![\dfrac{x}{10}=\dfrac{10}{18} \\\\\\x=10\cdot \dfrac{10}{18}\approx 5.5](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%7D%7B10%7D%3D%5Cdfrac%7B10%7D%7B18%7D%20%5C%5C%5C%5C%5C%5Cx%3D10%5Ccdot%20%5Cdfrac%7B10%7D%7B18%7D%5Capprox%205.5)
Hope this helps!
Answer:
-1 1/3 hope this helps
Step-by-step explanation: