X+6=11
X-11=-6
5x=25
2x=10
2x+15=25
Answer:
The answer I got was 16
16(y^2+4x^6)(y+2x^3)(y-2x^3)
Step-by-step explanation:
A. False. Consider the identity matrix, which is diagonalizable (it's already diagonal) but all its eigenvalues are the same (1).
b. True. Suppose

is the matrix of the eigenvectors of

, and

is the diagonal matrix of the eigenvalues of

:


Then

In other words, the columns of

are

, which are identically

, and these are the columns of

.
c. False. A counterexample is the matrix

which is nonsingular, but it has only one eigenvalue.
d. False. Consider the matrix

with eigenvalue

and eigenvector

, where

. But the matrix can't be diagonalized.
Answer:
=9
Step-by-step explanation:
3x9=27
27/3=9
Pretty sure the answer is 1.
Hope this helps.
(One point up from 1998, then 1 to the right gets you to 2000. 1/1 = 1)