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Orlov [11]
4 years ago
10

What is the solution to y=-x+3 and y=4x-2

Mathematics
1 answer:
DIA [1.3K]4 years ago
3 0

Answer: x=1

              y=2

Step-by-step explanation:

y=-x+3

y=4x-2

-----------

    y=y

-x+3=4x-2

3+2=4x+x

5=5x

x=1

y=-1+3

y=2

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When 5 is subtracted from the square of a number, the result is 4 times the number. Find the negative solution.
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Answer:

x = -1

Step-by-step explanation:

First, we can translate this statement to the equation

x^2-5=4x

Subtracting 4x from both sides gives us a quadratic equation:

x^2-4x-5=0

From here, we can factor the expression on the right to give us the equation's two solutions. The factored form will look like

(x+a)(x+b)=0

We need a + b = -4 and ab = -5, and picking a = 1 and b = -5 do the job there. Our expression factors then to (x + 1)(x - 5), giving us the equation

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3 0
3 years ago
PLEASE HELP ME ASAP
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Answer:

A=126

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Step-by-step explanation:

8 0
3 years ago
Can someone solve for x
Helen [10]

bearing in mind that, whenever we have an absolute value expression, is in effect a piece-wise function with a positive and a negative version of the expression, so

\bf |x^2-4x-5|=7\implies \begin{cases} +(x^2-4x-5)=7\\\\ -(x^2-4x-5)=7 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ +(x^2-4x-5)=7\implies x^2-4x-5=7\implies x^2-4x-12=0 \\\\\\ (x-6)(x+2)=0\implies x= \begin{cases} 6\\ -2 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ -(x^2-4x-5)=7\implies x^2-4x-5=-7\implies x^2-4x+2=0 \\\\\\ (x-2)(x-2)=0\implies x = 2

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3 years ago
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B I think that is the answer. If its not please let me know.
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4 years ago
Read 2 more answers
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