A person invests 8000 dollars in a bank. The bank pays 4.75% interest compounded daily. To the nearest tenth of a year , how lon
g must the person leave the money in the bank until it reaches 20400 dollars?
1 answer:
The number of days for which the money is left to reach the 20,400$ mark is; 21.28 days
<h3>Compound interest</h3>
The final amount to be reached is; $20400
The principal amount is; $8,000 and at. rate of 4.75 % compounded.
Hence, it follows that;
- 20400 = 8000(1+0.045)^(x)
Divide both sides of the equation by 8000; we have;
Take log of both sides;
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