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2 years ago

Answer this question PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Mathematics

1 answer:

yarga [219]2 years ago

3 0

Answer:

The last one.

Step-by-step explanation:

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A number , x,rounded to 1 decimal place is 3.7 what is the error interval for x

Phantasy [73]

<h2>Answer:</h2>

The error interval for x is:

[3.65,3.74]

<h2>Step-by-step explanation:</h2>

The number after rounding off is obtained as:

3.7

We know that any of the number below on rounding off the number to the first decimal place will result in 3.7:

3.65 3.66 3.67 3.68 3.69 3.70 3.71 3.72 3.73 3.74

( Because if we have to round off a number present in decimals to n place then if there is a number greater than or equal to 5 at n+1 place then it will result to the one higher digit at nth place on rounding off and won't change the digit if it less than 5 )

Hence, the error interval is:

[3.65,3.74]

8 0

2 years ago

Multiply the polynomial (x-5)(x^2+4x-2)

madreJ [45]

Answer:

x^3-x^2-22x+10

Step-by-step explanation:

7 0

3 years ago

If f(x)= x-3 over x and g(x)= 5x-4 what is the domain of (f•g)(x)

marusya05 [52]

Answer:

I attached the work to your problem below.

I hope it helps.

8 0

3 years ago

The CEO of a large corporation asks his Human Resource (HR) director to study absenteeism among its executive-level managers at

Fynjy0 [20]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given:

n = 30 is the sample size.

The mean $\bar X$ = 7.3 days.

The standard deviation = 6.2 days.

df = n-1

$= 30-1 \\ =29$

The importance level is $\alpha$ = 0.10

The table value is calculated with a function excel 2010:

$= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ = t_{al(2x-1)}= 1.699127$

The method for calculating the trust interval of 90 percent for the true population means is:

Formula:

$\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1} \frac{S}{\sqrt{n}}$

$=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29} \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127 (1.13196) \\\\=5.37 \leq \mu \leq 9.22 \\$

It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.

7 0

2 years ago

PLS HELP!! LOOK AT PICTURE!<br> Find the value of x in the similaur figures.

MAXImum [283]

Answer:

x=7

Step-by-step explanation:

14/28=x/14

x=7

8 0

2 years ago

Read 2 more answers