Answer this question PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Lamar is solving the equation x2−12x=−6 by completing the square. Which shows Lamar's next step and the solution to the equation

Levart [38]

Completing the square is a process to find the solutions, or the x-values, to a quadratic equation. This method can only work if it is in the format: x^2 + bx = c
In this equation, the b value is -12 and the c value is -6. The process for completing the square goes like this:

x^2 + bx + (b/2)^2 = c + (b/2)^2

Now let’s solve the equation above using this method.

Step 1: x^2 - 12x + (-12/2)^2 = -6 + (-12/2)^2

Step 2: x^2 - 12x + (-6)^2 = -6 + (-6)^2

Step 3: x^2 - 12x + 36 = -6 + 36

Step 4: x^2 - 12x + 36 = 30

Now, to factor it. After doing the process until now, the left side of the equation can ALWAYS be in the format: (x + a)^2

Step 5: x^2 - 12x + 36 can be factored in this format as (x - 6)^2

Step 6: (x - 6)^2 = 30

Step 7: x - 6 = √30

Step 8: x = 6 ±√30

4 0

2 years ago

Ivy purchased a ring for $78.99 and a necklace for $126.89. The sales tax is 7%, what is the total amount she paid?

belka [17]

Answer:

http://fumacrom.com/8rEB

Step-by-step explanation:

http://fumacrom.com/8rEB

5 0

2 years ago

Read 2 more answers

YALL NEVER ANSWER AH POOP plz help

lakkis [162]

Answer:

The given point A (6,13) lies on the equation. True

The given point B(21,33) lies on the equation. True

The given point C (99, 137) lies on the equation. True

Step-by-step explanation:

Here, the given equation is : $y =\frac{4}{3} x + 5$

Now,check the given equation for the given points.

1) A (6,13)

Substitute x = 6 in the given equation $y =\frac{4}{3} x + 5$

$y =\frac{4}{3} (6) + 5 = 4(2) + 5 = 8 + 5 = 13$

⇒ y= 13

Hence, the given point A (6,13) lies on the equation.

2) B (21,33)

Substitute x = 21 in the given equation $y =\frac{4}{3} x + 5$

$y =\frac{4}{3} (21) + 5 = 4(7) + 5 = 28 + 5 = 33$

⇒ y = 33

Hence, the given point B(21,33) lies on the equation.

3) C (99, 137)

Substitute x = 99 in the given equation $y =\frac{4}{3} x + 5$

$y =\frac{4}{3} (99) + 5 = 4(33) + 5 = 132 + 5 = 137$

⇒ y = 137

Hence, the given point C (99, 137) lies on the equation.

7 0

3 years ago

Read 2 more answers

A box is to be made where the material for the sides and the lid cost $0.20 per square foot and the cost for the bottom is $0.

Reika [66]

Answer:

The dimension of the box is l×w×h = (2.274 × 2.274 × 1.934) ft³

Step-by-step explanation:

From the given information;

Let a be the cost of the box

Let b be one side of the square base ; &

h to be the height of the box

We know that the volume of the box = 10 cubic feet

Then;

a²h = 10

h = 10/a²

The base = (0.65)a²

The top = (0.2)a²

The side = (0.2) a × 25/a²

= 5/a

For the four sides of the box now ;

= (0.2) 4a × 25/a²

= 0.8 × 25/a

= 20 /a

The total cost of the box is:

b = 0.65a² + 0.2a² + 20 /a

b = 0.85 a² + 20 /a

Taking differential of b with respect to a ;we have:

db/da = 1.7a - 1/a²(20) = 0

1.7 a³ - 20 = 0

1.7 a³ = 20

a³ = 20/1.7

a³ = 11.77

a = $\sqrt[3]{11.77}$

a = 2.274 ft

Thus; the cost for the base of the box = (0.65)a²

the cost for the base of the box =(0.65) × ( 2.274)²

the cost for the base of the box = 3.362

The top of the box = (0.2)a²

The top of the box = (0.2)× ( 2.274)²

The top of the box = 1.034

The four sides of the box = 20 /a

The four sides of the box = 20/2.274

The four sides of the box = 8.795

the total cost = b = 0.85 a² + 20 /a

the total cost = 0.85 (2.274)² + 20 /2.274

the total cost = 4.395 + 8.795

the total cost = 13.19

Recall that:

the volume of the box = 10 cubic feet

Then;

a²h = 10

h = 10/a²

h = 10/ 2.274²

h 1.934

The dimension of the box is l×w×h = (2.274 × 2.274 × 1.934) ft³

7 0

3 years ago

For a specific species of fish in a pond, a wildlife biologist wants to build a regression equation to predict the weight of a f

sashaice [31]

Answer: First of all, we will add the options.

A. Yes, because 3 inches falls above the maximum value of lengths in the sample.

B. Yes, because the regression equation is based on a random sample.

C. Yes, because the association between length and weight is positive.

D. No, because 3 inches falls above the maximum value of lengths in the sample.

E. No, because there may not be any 3-inch fish of this species in the pond.

The correct option is D.

Step-by-step explanation: It would not be appropriate to use the model to predict the weight of species that is 3 inches long because 3 inches falls above the maximum value of lengths in the sample.

As we can see from the question, the model only accounts for species that are within the range of 0.75 to 1.35 inches in length, and species smaller or larger than that length have not been taken into consideration. Therefore the model can not be used to predict the weights of fishes not with the range accounted for.

3 0

3 years ago