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Ray Of Light [21]
3 years ago
8

PLS HELP 30 PTS!!!Use the coordinate plane to help you identify the length of each leg then use the Pythagorean Theorem to find

the length of CD
Type your answer in the box.

Note: Type in only numeric part of the answer. Round your answer to the nearest hundredth.

Example: 12.70

Mathematics
2 answers:
shusha [124]3 years ago
7 0

Answer:

it says 15 points not 30

Step-by-step explanation:

Murrr4er [49]3 years ago
4 0

Answer:

10.30

Step-by-step explanation:

Pythagorean Theorem is a^{2} + b^{2} = c^{2}.  The short leg(a) is 5 units long and the long leg(b) is 9 units long.  CD is the hypotenuse, the longest side (c).

5^{2} +9^{2} =c^{2}

25+81=c^{2}

106=c^{2}

\sqrt{106} = \sqrt{c^{2} }

10.29563014 = c

Rounded to the nearest hundredth, 10.30

To check this is correct, the hypotenuse is the longest side, and 10.30 is longer than 5 and 9.  

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The volumes of two cylindrical cans of the same shape vary directly as the cubes of their radii. If a can with a six-inch radius
Cerrena [4.2K]

Answer:

The second similar can with a radius of 24-inch radius will hold 12 gallons

Step-by-step explanation:

The given parameters are;

The volumes of the cylindrical can ∝ (The radius of the cans)³

The volume of first can, V₁ = 1¹/₂ pints

The radius of the first can, r₁ = 6-inch

The radius of the second can, r₂ = 24-inch

Therefore, we have;

V ∝ r³

V = k × r³

∴ 1¹/₂ pints ∝ (6 in.)³

1¹/₂ pints = 43.3125 in³

∴ 43.3125 in³ = k × 216 in.³

The constant of proportionality, k = 43.3125/216 = 0.2005208333

Therefore, we have for the second can, we have;

V₂ = k × r₂³ = 43.3125/216 × (24 in.)³ = 2772 in.³

The volume of the second can = 2772 in.³

1 in.³ = 0.004329 gallons

∴ 2772 in.³ = 2772 × 0.004329 gallons = 12 gallons

Therefore, the volume the second similar can with a 24-inch radius will hold = 12 gallons.

8 0
3 years ago
Tim wants to ride his bike for 25 miles or less on some mountains bike trails . The table shows the distance of three different
Basile [38]

yo sup??

the sum of trails taken should be less than 25 miles

Black bear=B

Eagle Ridge=E

Doe Run=D

(btw names sound cool XD)

we will now try different combinations

B+E=7 1/2 ++ 10 1/4 which is clearly less than 25

B+D=7 1/2 + 8 3/4 which also less than 25

E+D=10 1/4 + 8 3/4 which is also less than 25

B+D+E=7 1/2 + 10 1/4 + 8 3/4 which is greater than 25

Therefore only the 1st,2nd and 3rd case are possible

Hope this helps.

7 0
2 years ago
In a candy mix there are 4 green bars for every 3 red bars. How many red bars are there if there are 200 green bars
erastovalidia [21]

Answer:

Since there are 4 green bars for every 3 red bars and we are trying to find the number of red bars if there are 200 green bars, we can create the ratio:

4 x : 3 y

Where  x  is equal to the number of green bars and  y is the number of red bars.

We know the number of green bars is equal to 200, so we can divide it by 4, giving us:

200 /4=50

Then we can solve for  y , the number of red bars.

// Multiple y  by 50

3 ⋅ 50 = 150

So for every 4 green bars, there are 3 red bars.

For every 200 green bars, there are 150 red bars

Step-by-step explanation:

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