PLS HELP 30 PTS!!!Use the coordinate plane to help you identify the length of each leg then use the Pythagorean Theorem to find
the length of CD
Type your answer in the box.
Note: Type in only numeric part of the answer. Round your answer to the nearest hundredth.
Example: 12.70
2 answers:
Answer:
it says 15 points not 30
Step-by-step explanation:
Answer:
10.30
Step-by-step explanation:
Pythagorean Theorem is
+
=
. The short leg(a) is 5 units long and the long leg(b) is 9 units long. CD is the hypotenuse, the longest side (c).
+
=![c^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D)
25+81=![c^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D)
106=![c^{2}](https://tex.z-dn.net/?f=c%5E%7B2%7D)
= ![\sqrt{c^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7Bc%5E%7B2%7D%20%7D)
10.29563014 = c
Rounded to the nearest hundredth, 10.30
To check this is correct, the hypotenuse is the longest side, and 10.30 is longer than 5 and 9.
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Answer:
1/3
Step-by-step explanation:
3+2+1=6 (Adding all the fish together)
There is 2 Bulegill fish
so it would be 2/6
Or it being simplified, 1/3
The answer is 5,22 simplified
Answer:
Answer is 11/2.
Step-by-step explanation:
I hope it's helpful!
Answer:
The other factors are:
and ![(x^2+2x+4)](https://tex.z-dn.net/?f=%28x%5E2%2B2x%2B4%29)
Step-by-step explanation:
Given
Polynomial: ![x^4 + 2x^3 - 8x - 16](https://tex.z-dn.net/?f=x%5E4%20%2B%202x%5E3%20-%208x%20-%2016)
Factor: ![x + 2](https://tex.z-dn.net/?f=x%20%2B%202)
Required
Find other factors
![x^4 + 2x^3 - 8x - 16](https://tex.z-dn.net/?f=x%5E4%20%2B%202x%5E3%20-%208x%20-%2016)
Group into two
![x^4 + 2x^3 - 8x - 16 = (x^4 + 2x^3) - (8x + 16)](https://tex.z-dn.net/?f=x%5E4%20%2B%202x%5E3%20-%208x%20-%2016%20%3D%20%28x%5E4%20%2B%202x%5E3%29%20-%20%288x%20%2B%2016%29)
Factorize:
![x^4 + 2x^3 - 8x - 16 = x^3(x + 2) -8 (x + 2)](https://tex.z-dn.net/?f=x%5E4%20%2B%202x%5E3%20-%208x%20-%2016%20%3D%20x%5E3%28x%20%2B%202%29%20-8%20%28x%20%2B%202%29)
Factor out common term
![x^4 + 2x^3 - 8x - 16 = (x^3 -8)(x + 2)](https://tex.z-dn.net/?f=x%5E4%20%2B%202x%5E3%20-%208x%20-%2016%20%3D%20%28x%5E3%20-8%29%28x%20%2B%202%29)
Rewrite
as ![x^3 + 2x^2 - 2x^2+ 4x - 4x - 8](https://tex.z-dn.net/?f=x%5E3%20%2B%202x%5E2%20-%202x%5E2%2B%204x%20%20-%204x%20-%208)
![x^4 + 2x^3 - 8x - 16 = (x^3 + 2x^2 - 2x^2+ 4x - 4x - 8)(x + 2)](https://tex.z-dn.net/?f=x%5E4%20%2B%202x%5E3%20-%208x%20-%2016%20%3D%20%28x%5E3%20%2B%202x%5E2%20-%202x%5E2%2B%204x%20%20-%204x%20-%208%29%28x%20%2B%202%29)
Rearrange the terms
![x^4 + 2x^3 - 8x - 16 = (x^3 + 2x^2 + 4x - 2x^2 - 4x - 8)(x + 2)](https://tex.z-dn.net/?f=x%5E4%20%2B%202x%5E3%20-%208x%20-%2016%20%3D%20%28x%5E3%20%2B%202x%5E2%20%2B%204x%20-%202x%5E2%20-%204x%20-%208%29%28x%20%2B%202%29)
Factorize
![x^4 + 2x^3 - 8x - 16 = (x(x^2+2x+4)-2(x^2+2x+4))(x + 2)](https://tex.z-dn.net/?f=x%5E4%20%2B%202x%5E3%20-%208x%20-%2016%20%3D%20%28x%28x%5E2%2B2x%2B4%29-2%28x%5E2%2B2x%2B4%29%29%28x%20%2B%202%29)
Factor out ![(x^2+2x+4)](https://tex.z-dn.net/?f=%28x%5E2%2B2x%2B4%29)
![x^4 + 2x^3 - 8x - 16 = (x-2)(x^2+2x+4)(x + 2)](https://tex.z-dn.net/?f=x%5E4%20%2B%202x%5E3%20-%208x%20-%2016%20%3D%20%28x-2%29%28x%5E2%2B2x%2B4%29%28x%20%2B%202%29)
So, the other factors are:
and ![(x^2+2x+4)](https://tex.z-dn.net/?f=%28x%5E2%2B2x%2B4%29)
Answer:
Step-by-step explanation:
It's 6