The Solution:
Given:
Center = (0,0)
Point A = (-5,2) being a point on the circle.
We are required to check if point P = (2,-5) is on the circle.
Solving the given problem graphically, we have:
From the above graph, it is clear that point P(2,-5) is a point on the circle.
Answer: 5/2
5/6 / 1/3 = 2.5
2.5 in fraction = 5/2
Answer:
Step-by-step explanation:
8x + 12 = 3x + 5x + 12
8x + 12 = 8x + 12
Bringing like terms on one side
8x - 8x = 12 - 12
x = 0
For this case we have the following vectors:
![a = (2,1, -4) b = (- 3,0,1) c = (- 1, -1,2)](https://tex.z-dn.net/?f=a%20%3D%20%282%2C1%2C%20-4%29%0A%0Ab%20%3D%20%28-%203%2C0%2C1%29%0A%0Ac%20%3D%20%28-%201%2C%20-1%2C2%29)
The dot product of two vectors is a scalar.
The point product consists of multiplying component by component and then adding the result of the multiplication of each component.
For the product point of the vectors a and b we have:
Answer:
The product point of the vectors a and b is:
With pythagorean theorem and working backwards, you do 8100-1225 to get 6875, you then get the square root of that to get x=82.91 or rounded to 82.92