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3 years ago

Type the integer that makes the following subtraction sentence true: _____ − –99 = 3

Mathematics

2 answers:

yarga [219]3 years ago

8 0

Your answer should be 102

Liula [17]3 years ago

6 0

Answer:

-96

Step-by-step explanation:

when there are two subtraction signs it is basically a plus sign

___ + 99 = 3

then you can subtract 99 from both sides

___ = -96

your answer is -96

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100 points, questions on the picture

Alexus [3.1K]

Answer:

Step-by-step explanation:

22a) width = 3x-1

2(3x-1)

6x-2 = length

22b) P = 2* length + 2* width

P= 2(6x-2) +2(3x-1)

P= 12x -4 +6x-2 ; 18x-6

22c) P = 18(5)-6

P = 84 cm

8 0

3 years ago

Read 2 more answers

W = x + yz what does Z equal?

Serhud [2]

Z = z u need numbers or something if z is supposed to be a number

8 0

3 years ago

Construct the discrete probability distribution for the random variable described. Express the probabilities as simplified fract

lisov135 [29]

Answer:

$P(X = 0) = 0.03125$

$P(X = 1) = 0.15625$

$P(X = 2) = 0.3125$

$P(X = 3) = 0.3125$

$P(X = 4) = 0.15625$

$P(X = 5) = 0.03125$

Step-by-step explanation:

For each toss, there are only two possible outcomes. Either it is tails, or it is not. The probability of a toss resulting in tails is independent of any other toss, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Fair coin:

Equally as likely to be heads or tails, so $p = 0.5$

5 tosses:

This means that $n = 5$

Probability distribution:

Probability of each outcome, so:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.5)^{0}.(0.5)^{5} = 0.03125$

$P(X = 1) = C_{5,1}.(0.5)^{1}.(0.5)^{4} = 0.15625$

$P(X = 2) = C_{5,2}.(0.5)^{2}.(0.5)^{3} = 0.3125$

$P(X = 3) = C_{5,3}.(0.5)^{3}.(0.5)^{2} = 0.3125$

$P(X = 4) = C_{5,4}.(0.5)^{4}.(0.5)^{1} = 0.15625$

$P(X = 5) = C_{5,5}.(0.5)^{5}.(0.5)^{0} = 0.03125$

5 0

3 years ago

A very short quiz has one multiple-choice question with five possible choices (a, b, c, d, e) and one true or false question. As

earnstyle [38]

<h3>a. The probability that both questions are answered </h3><h3>correctly = 0.1 </h3><h3>b. The probability that only one questions is </h3><h3>answered correctly = 0.5</h3><h3>c. The probability that none questions is </h3><h3>answered correctly = 0.4</h3><h3>d. The probability that only question 1 is </h3><h3>answered correctly = 0.1</h3><h3>e. The probability that only question 2 is answered</h3><h3> correctly = 0.4</h3>

Step-by-step explanation:

Here given: The quiz has two questions.

Question 1 is an Multiple Choice Question with 5 options, out of which only <u>one option is the correct option</u>.

So, the probability of answering the question 1 correctly = $(\frac{1}{5} ) = 0.2$

Question 2 is an true false question with 2 options, out of which only <u>one option is the correct option</u>.

So, the probability of answering the question 2 correctly = $(\frac{1}{2} ) = 0.5$

Now, let us consider each part asked:

a. The probability that <u>both questions are answered correctly </u>

= (0.2)(0.5) = 0.1

b. The probability that <u>only one questions is answered correctly </u>

= 1 - [both right or both wrong] = 1 - [0.1 + (0.5)(0.8)] = 1-[0.5] = 0.5

c. The probability that <u>none questions is answered correctly </u>

= P(not Q1) x P(not Q2) = (1- P(Q1) )(1- P(Q2)) = (1-0.5)(1-0.2) = 0.4

d. The probability that only<u> question 1 is answered correctly </u>

= P( Q1) x P(not Q2) = (1- P(Q1) )(P(Q2)) = (1-0.5)(0.2) = 0.1

e. The probability that only<u> question 2 is answered correctly </u>

= P( not Q1) x P( Q2) = (P(Q1) )(1- P(Q2)) = (0.5)(1-0.2) = 0.4

3 0

3 years ago

Factor 12a^2-15ab-16a+20b

ollegr [7]

Answer:

(4a-5b) (3a-4)

Step-by-step explanation:

12a^2-15ab-16a+20b

(12a^2-15ab) + (20b-16a) Factor out 3a

Factor out 4 from 20b-16a: 4(5b-4a)

3a(4a-5b)(5b-4a)

4(5b-4a)= -4(4a-5b)

3a(4a-5b)(4a-5b)

(4a-5b)(3a-4)

5 0

2 years ago