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Assuming you meant a "circular cross-section" of 201.06 in².
so, we know if we cut the sphere like a cantaloupe, in half, the circular inner-part of the cantaloupe will have an area of 201.6 in².
keeping in mind that, the radius of that circular section, is the same radius of the sphere, what is it anyway?
so, we know if we cut the sphere like a cantaloupe, in half, the circular inner-part of the cantaloupe will have an area of 201.6 in².
keeping in mind that, the radius of that circular section, is the same radius of the sphere, what is it anyway?
Answer:
Area under the normal curve: 0.6915.
69.15% probability of putting less than 24 ounces in a cup.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
You have been asked to calculate the probability of putting less than 24 ounces in a cup.
pvalue of Z when X = 24. So
has a pvalue of 0.6915
Area under the normal curve: 0.6915.
69.15% probability of putting less than 24 ounces in a cup.