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tester [92]
3 years ago
7

what is an equation of the line that is perpendicular to y=-4/5x+3 and passes through rhe point (4, 13)?

Mathematics
2 answers:
bezimeni [28]3 years ago
6 0
If a line is perpendicular to another line, it has an opposite reciprocal slope. The opposite reciprocal of -4/5 is 5/4.

Based on the picture I drew, the y intercept is (0,3), so the equation should be y = 5/4 + 3.

8090 [49]3 years ago
4 0

Answer:

y = 5/4 x + 8


Step-by-step explanation:

y= - 4/5x + 3

Slope = -4/5

Perpendicular slope = 5/4


Point (4, 13)

13 = 5/4 (4) + b

13 = 5 + b

b = 8


y = 5/4 x + 8

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Answer:

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What is the probability of getting either a sum of 66 or at least one 66 in the roll of a pair of​ dice?
Sindrei [870]
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7 0
3 years ago
Please find the slope of (-2, 4) and (3, -5)
DIA [1.3K]

Answer:

The slope of the line = m = -9/5

Step-by-step explanation:

Given the points

  • (-2, 4)
  • (3, -5)  

Determining the slope between (-2, 4) and (3, -5)

(x₁, y₁) = (-2, 4)

(x₂, y₂) = (3, -5)

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]  

                 =  [-5 - 4] / [3 - (-2)]

                 = [-9] / [3 + 2]

                 = -9/5

Thus, the slope of the line = m = -9/5  

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sattari [20]
What you have written down is correct, x=-3
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3 years ago
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