My guess would be distributive. i maybe be wrong so don't get mad if I'm wrong.
If you multiply 6 * 5 you get 30. 30 * 103 = 3,090
There are 2 zeros in the product of (6x5)x103
First u have to find the square root for the number and then answer all of the root question then u have to find the angels
Area of a circle is PI x r^2
The radius of the large circle is shown as 8 m
The diameter of A is the radius of the large circle which is 8 m so the radius would be 4 m
The radius of the small circle would be 2m
Area of large circle = pi x 8^2 = 64pi = 200.96 square m
Area of middle circle = pi x 4^2 = 16pi = 50.24 square m.
Area of small circle = pi x 2^2 = 4pi = 12.56 square m.
The area of the shaded region = large - middle + small
Area = 64pi - 16pi + 4pi = p2pi square m or 200.96 -50.24 + 12.56 = 163.28 square m.
Answer:
11/12
Step-by-step explanation:
2 3/4 = 2·(4/4) + 3/4 = (8/4) +(3/4) = (8+3)/4 = 11/4
Then your problem becomes ...
(11/4) / 3 = (11/4) · (1/3) = (11·1)/(4·3) = 11/12
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The numerator and denominator have no common factors, so this is lowest terms.
