Hey guys ! Can anyone help me with these problems please and thanks
1 answer:
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3rd degreee has 3 zeros
easy
x=-6
x+6=0
x=3
x-3=0
x=4
x-4=0
f(x)=(x+6)(x-3)(x-4)
expanded
f(x)=
easy
x=-6
x+6=0
x=3
x-3=0
x=4
x-4=0
f(x)=(x+6)(x-3)(x-4)
expanded
f(x)=