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2 years ago

Over the period of a year, Sam’s net worth increased. Which of the following could be true?

Mathematics

1 answer:

MAXImum [283]2 years ago

7 0

Answer:

Sam's assets increased by more than his liabilities.

Step-by-step explanation:

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If y=8 when x =3, find y when x=45

Art [367]

Let's make things easier by simplifying things.

y = 8 and x = 3 is more likely to be understood as a ratio. So for the rest of the answer, their relationship would be represented as y:x

Thus: y:x = 8:3

The problem would be finding y when x = 45

Let us proceed on using the previous equation and substitute x with 45 which would look like this:

y:45 = 8:3

Ratios can also be expressed as fractions which would make things more understandable and easy to solve. So the new form of our equation would be like this:

y/45 = 8/3

Then we proceed with a cross multiplication where the equation becomes like as what is shown below:

3y = 45 * 8

From there, you can solve it by multiplying 45 and 8 then dividing the product with 3 to get y

3y = 360

y = 120

Another way of looking at the problem, especially problems like these, is to take the whole question or statement as an equation. it would probably look like this:

y = 8 when x = 3 : y = ? when x = 45

This would make you understand what approach you can use to solve the given problem.

5 0

3 years ago

Read 2 more answers

Consider the following hypothesis test:

Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

$H_0: \mu\leq50\\\\H_a:\mu> 50$

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809$

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24$

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0

4 years ago

Syrus is buying a tent with the dimensions 4ft 6ft the volume inside the tent is 36feet. Syrus isn't sure if he will be able to

Alborosie

Answer:

Step-by-step explanation:

triangle prism volume=1/2LWH

36=1/2(4)(6)H

36=12h

h=3

3 0

3 years ago

What strategy is (5 x 200) plus (5 x 16)

Volgvan

The answer to this is 1080

4 0

4 years ago

Read 2 more answers

5 and 1/3 × 3 and 3/4

tresset_1 [31]

We'll first off convert the mixed fractions to "improper", and then multiply.

$\bf \stackrel{mixed}{5\frac{1}{3}}\implies \cfrac{5\cdot 3+1}{3}\implies \stackrel{improper}{\cfrac{16}{3}}
\\\\\\
\stackrel{mixed}{3\frac{3}{4}}\implies \cfrac{3\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{15}{4}}
\\\\\\
\cfrac{16}{3}\times \cfrac{15}{4}\implies \cfrac{15}{3}\times \cfrac{16}{4}\implies 5\times 4\implies 20$

6 0

3 years ago