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lorasvet [3.4K]
3 years ago
11

Can someone help me please?

Mathematics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0
My ans is 3,4,5 hope it helpsssss
nikitadnepr [17]3 years ago
5 0
The answers are 3,4 and 5 check the image for more context

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3у(6у+2х)-(х+3у)^2 при х=√2 , у=√7 <br><br> 4ab/+4b*(a/4b-4b/a) при a=4√5+3,b=√5-9
kompoz [17]
\pi is the answer.
5 0
4 years ago
Find the area of this figure
Romashka [77]

Answer: 125 squared ft

<em />

<em>Area of the big rectangle </em>⬜️<em>, 15ft x 10ft = 150 square ft</em>

<em>Area of the small square(which is spaced), 5ft x 5ft = 25 squared ft</em>

<em>Area of the give figure, 150squared ft- 25squared ft = 125 squared ft</em>

6 0
3 years ago
Read 2 more answers
Solve 5x2-2x-8=0 using the quadratic formula.
choli [55]

Answer:

x=\frac{1+\sqrt{41}}{5},\\x=\frac{1-\sqrt{41}}{5}

Step-by-step explanation:

The quadratic formula states that the solutions for a quadratic is standard form ax^2+bx+c are equal to x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}.

In 5x^2-2x-8=0, we can assign the values:

  • a of 5
  • b of -2
  • c of -8

Thus, we have:

x=\frac{-(-2)\pm \sqrt{(-2)^2-4(5)(-8)}}{2(5)},\\x=\frac{2\pm \sqrt{164}}{10},\\\begin{cases}x=\frac{2+ \sqrt{164}}{10}, x=\frac{1}{5}+\frac{\sqrt{41}}{5}=\frac{1+\sqrt{41}}{5}\\x=\frac{2- \sqrt{164}}{10}, x=\frac{1}{5}-\frac{\sqrt{41}}{5}=\frac{1-\sqrt{41}}{5}\end{cases}

6 0
3 years ago
Read 2 more answers
Use the number line to describe how to round 450 to the nearest hundred
Masja [62]
4 or less let it rest 5 or more let it score. It would be 500
3 0
4 years ago
Find the solution<br><br>|3x + 12| = 24​
katen-ka-za [31]

Answer:

x = 4 or x = -12

Step-by-step explanation:

|3x + 12| = 24

3x + 12 = 24 or -(3x + 12) = 24

       3x = 12 or -3x - 12 = 24

           x = 4 or -3x = 36

           x = 4 or x = -12

7 0
4 years ago
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