Answer:
0
Step-by-step explanation:
Let's consider each of the options;
A) The range is the values that y can be of the function f(x). We can see that no matter what x values you put in, f(x)>0. It will never be negative. Although, if you put (1/2)^2, you can get a y value of (1/4) so this statement is incorrect.
B) It would have to put in the x or y value into the function and check. f(0)=(1/2)^0
You know that anything to the zero-th power gives 1, therefore, this statement is correct.
C) Again, if you put in a value such as (1/2)^2, you would be getting a number that is smaller than 1/2, so it isn't always increasing.
D) Again, it is possible to input any value in x and you would still be getting a positive y-value, therefore, this statement is incorrect.
Hope I helped :)
The point that the graphs of f and g have in common are (1,0)
<h3>How to get the points?</h3>
The given functions are:
f(x) = log₂x
and
g(x) = log₁₀x
We know that logarithm of 1 is always zero.
This means that irrespective of the base, the y-values of both functions will be equal to 0 at x=1
Therefore the point the graphs of f and g have in common is (1,0).
Learn more about graph on:
brainly.com/question/19040584
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To solve this, since you know that h(x) is 11 and that it also equals -4x+3, you set them equal to one another which would look like this: 11=-4x+3.
Then, to solve for x, which is what I am assuming the question is asking, you would subtract 3 from both sides to isolate -4x, which would result in this:
-4x=8
Now, to solve for x, divide both sides by -4, and you get your answer which is x=-2
