Question

Convert the following to powers first then simplify and then write answer as a radical ​

Answer 1

Answer:

$\sqrt[15]{m^2n^4}$

Step-by-step explanation:

$(\sqrt[5]{m^2n^4} )^{\frac{1}{3}}\\\\\implies( (m^2n^4)^{\frac{1}{5}})^{\frac{1}{3}}\\\\\implies (m^2n^4)^{\frac{1}{5}\times \frac{1}{3}}\\\\\implies (m^2n^4)^{\frac{1}{15}}\\\\\implies (m^2)^{\frac{1}{15}} (n^4)^{\frac{1}{15}}\\\\\implies m^{\frac{2}{15}} n^{\frac{4}{15}}$

$\sqrt[15]{m^2n^4}$