Try to get all the x'es to the right side
Leg CB = x and leg DE = y - 1. Becuase of the markings on the triangles, we know that CB = DE; therefore, x = y - 1. So let's use that x value when we set the 2 hypotenuses equal to each other. Before any substition, 3x - 2 = 2y + 1. Subbing in for x we have 3(y - 1) - 2 = 2y + 1. And 3y - 3 - 2 = 2y + 1. Combining like terms we have y = 6. If y = 6, we will sub it into the leg equation to find x. x = y - 1; therefore, x = 6 - 1 and x = 5. There you go! x = 5 and y = 6
If you plug in 12 for x.
Your expression is y= 2(12)/3y
then you just solve for Y
X+y = 10
x*y= -600
x = -y + 10
Plug this into the equation below
(-y+10) * y = -600
-y^2 +10y + 600 = 0
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