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2 years ago

Find the cosine of ∠J.

Mathematics

1 answer:

brilliants [131]2 years ago

3 0

Answer:

√94

Step-by-step explanation:

i think that is the answer

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Solve for x: 14-x= 5

tia_tia [17]

Answer:

x = 9

Step-by-step explanation:

We are going to isolate x

14 - x = 5

subtract 14 from 5

-x = -9

multiply both sides by -1 to make x positive

x = 9

6 0

3 years ago

Read 2 more answers

A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r

svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, $h^2 + b^2 = 16^2 = 256 \dotsc\;(1)$ because it is a right angle triangle.

It is given that $\frac{db}{dt} = 1$

Now differentiate (1) with respect to t (time) :

$\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}$

$\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}$

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that $16 \sin{\theta} = b$ . When b = 8, then $\theta = \arcsin{0.5} = \ang{30}$ .

Differentiate the above equation w.r.t t

$\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}$

c. The area of the triangle is given by $A = 0.5\times h \times b$ . Differentiating w.r.t t,

$\displatstyle{\frac{dA}{dt} = 0.5 b \frac{dh}{dt} + 0.5 h \frac{db}{dt}}$

Plugging in b = 8, h = 13.856, $\frac{dh}{dt} = -0.588$ ,

$\frac{dA}{dt} = -2.352 + 6.928 = \mathbf{4.576 ft^2/sec}$

8 0

3 years ago

Please please answer this correctly

Aliun [14]

The answer is 10 as the diameter because it says to estimate pi as 3. Since we know the circumference is 30 we can reverse it to find the diameter, since Circumference is pi time diameter.

3 0

3 years ago

Read 2 more answers

The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance betw

Likurg_2 [28]

Diameter of the basketball rim = 18 inchesCircumference of the standard basketball = 30 inches
Area of circle = π r²
Basketball rim = 3.14 * (18/2)² = 3.14 * 9² = 3.14 * 81 = 254.34 in²
Circumference of a circle = 2 π r30 = 2 * 3.14 * rr = 30 / (2*3.14) = 30 / 6.28 = 4.78 inches
Standard basketball = 3.14 * (4.78)² = 3.14 * 22.85 = 71.75 in²
254.34 - 71.75 = 182.59 in²

5 0

3 years ago

Read 2 more answers

Hii can someone help me this is science I didn’t mean to put math and this is 6th grade work btw I’ll give you BRAINLIST if you

algol13

Answer:

Lunar, and solar eclipse!

Step-by-step explanation:

This first one, is pretty easy! An easy way to remember it is solar is sun (both start with s), so lunar is moon!

The second one is solar eclipse, since the moon passes between the sun and earth, which causes the moon's shadow to fall on earth!

I hope this helps, and I'm here if you need anything else! <3

6 0

3 years ago