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Ksju [112]
2 years ago
12

The exponential function f, whose graph is given below, can be written as​

Mathematics
1 answer:
Mazyrski [523]2 years ago
3 0

Answer:

f(x) = 2·3^x

Step-by-step explanation:

We have the general equation of exponential functions as

y= a*b^x

We are given that the point (0,2) is on the graph so

when x= 0, y= 2

If we substitute in the general equation we see that

2 = a*b^0, any number to the power 0 is 1

2 = a

We were also given that point (1, 6 ) is on the graph;

If we substitute in our new found equation we see that

y=2·b^x

6 = 2·b^1 , any number to the power 1 is itself and

                 divide both sides by 2

3 = b

f(x) = 2·3^x

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3 years ago
Consider the parent function f(x) = x^2 and the transformed function f(x) =- 5(x - 4)^2 – 8. Identify the
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Given:

The parent function is

f(x)=x^2

Consider the transformed function is g(x) instead of f(x) because both functions are different.

g(x)=-5(x-4)^2-8

Step-by-step explanation:

We have,

f(x)=x^2

g(x)=-5(x-4)^2-8

It can be written as

g(x)=-5f(x-4)-8            ...(i)

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Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If 0<|k|<1, then the graph compressed vertically by factor k and if |k|>1, then the graph stretch vertically by factor k.

If k is negative, then f(x) is reflected across the x-axis to get g(x).

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

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On comparing (i) and (ii), we get

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Therefore, the function f(x) reflected across the x-axis, stretched vertically by factor 5 and shifted 4 units right 8 units down to get g(x).

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