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saveliy_v [14]
3 years ago
15

Think about the pseudocode that you developed for your adventure game in this unit. Would it have been easier to create a flowch

art? Why or why not?
Computers and Technology
1 answer:
katovenus [111]3 years ago
5 0

Answer:

it may not be easy

Explanation:

because am using a phone not a cuputer

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Organizational structures with one or more layers of authority between top-level management and employees are known as vertical
r-ruslan [8.4K]

The organizational structure described here, which is known as vertical organizational structure, is also commonly identified as tall organizations.

They usually have hierarchical structures, with the CEO being at the very top of the layer. Tall organization have multiple levels, compared to its counterpart, the flat organization or horizontal, which would only have one level.  

8 0
3 years ago
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Bluetooth is a common wireless protocol used to make pan connections. <br> a. True <br> b. False
Minchanka [31]
 a. True  This  is because it covers only a short distance  and allows  sharing of data between short distances(PAN) 
5 0
4 years ago
Write a method that takes a Regular Polygon as a parameter, sets its number of sides to a random integer between 10 and 20 inclu
Fantom [35]

Answer:

Answered below

Explanation:

//Program is written in Java programming language

Class RegularPolygon{

int sides = 0;

int length = 0;

}

public void randomize(RegularPolygon polygon){

int randomSides = (int) 10 + (Math.random() * 20);

double randomLength = 5 + (Math.random() * 11);

polygon.sides = randomSides;

polygon.length = randomLength;

}

8 0
3 years ago
Fifty-three percent of U.S households have a personal computer. In a random sample of 250 households, what is the probability th
aleksley [76]

Answer:

The correct Answer is 0.0571

Explanation:

53% of U.S. households have a PCs.

So, P(Having personal computer) = p = 0.53

Sample size(n) = 250

np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10

So, we can just estimate binomial distribution to normal distribution

Mean of proportion(p) = 0.53

Standard error of proportion(SE) =  \sqrt{\frac{p(1-p)}{n} } = \sqrt{\frac{0.53(1-0.53)}{250} } = 0.0316

For x = 120, sample proportion(p) = \frac{x}{n} = \frac{120}{250} = 0.48

So, likelihood that fewer than 120 have a PC

= P(x < 120)

= P(  p^​  < 0.48 )

= P(z < \frac{0.48-0.53}{0.0316}​)      (z=\frac{p^-p}{SE}​)  

= P(z < -1.58)

= 0.0571      ( From normal table )

6 0
3 years ago
How does a cat get out of a bush?
Alex17521 [72]

Answer:

that lil mf crawls through the bush

Explanation:

hes fast ngl

7 0
3 years ago
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