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fredd [130]
3 years ago
7

Which of the following graphs represents a quadratic equation with roots of -5 and 2.5

Mathematics
1 answer:
tiny-mole [99]3 years ago
6 0

Answer:

B

Step-by-step explanation:

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Write a variable expression for this amount.<br> fourteen times x<br> Type the correct answer.
Ymorist [56]

Answer:

14x

Step-by-step explanation:

14x = 14 x (x) = 14(x)

3 0
3 years ago
The Marquez family has 4/5 pint of ice cream, if each family member is served 1/5 pint of ice cream, how many people will get ic
julia-pushkina [17]

Answer: 4 people

Step-by-step explanation:

4 times 1/5= 4/5

The 4 goes on top ( numerator ) and the 5 would go on the bottom ( denominator )

Also another way to solve this is to use decimal form.

4 times 0.2 ( 0.2=1/5 )= 0.8

8 0
3 years ago
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How can I divide decimals
shusha [124]
You can write the problem with a division box, move the divisor decimal point the amount of spaces that it would take to make the number whole. Move the decimal if the dividend the same amount of spaces as the divisor. Move the decimal point directly up above the division bar, divide, check your work
4 0
3 years ago
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Find the surface area of the equilateral triangular pyramid.
Alenkinab [10]
We know that
[surface area of the triangular pyramid]=area of the base+3*[area of lateral triangles]
area of the base=12*8/2-----> 48 cm²

area of one lateral triangle=12*10/2-----> 60 cm²
[surface area of the triangular pyramid]=48+3*[60]-----> 228 cm²

the answer is the option 
<span>B) 228 cm2</span>
8 0
3 years ago
Find the values of p and q such that 4x-5-x^2=q-(x+p)^2
Solnce55 [7]

Answer:

p = - 2 , q = - 1

Step-by-step explanation:

Rearrange the left side into standard form

- x² + 4x - 5

Factor out - 1 from - x² + 4x

= - (x² - 4x) - 5

Using the method of completing the square

add/subtract ( half the coefficient of the x- term)² tp x² - 4x

= - (x² + 2(- 2)x + 4 - 4) - 5

= - (x - 2)² - (- 4) - 5

= - (x - 2)² + 4 - 5

= - 1 - (x - 2)²

Comparing to q - (x + p)²

with p = - 2 and q = - 1

4 0
3 years ago
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