You have to take out the "|"
8x-1 ≤ 2x+11
8x-2x ≤ 11+1
6x ≤ 12
X ≤ 12/6
X ≤ 2
It hits the ground at h=0
0=-16t^2-16t+96
undistribute -16
0=-16(t^2+t-6)
factor
0=-16(t-2)(t+3)
set to zero
0=t-2
2=t
t+3=0
t=-3, nope, we can't have negative time
at t=2, or 2 seconds
-1,+2,+4,+6,+8
please mark brainliest
Answer:
Dilation of 3
Step-by-step explanation:
Answer:
$1.4 B per year
Step-by-step explanation:
