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cluponka [151]
2 years ago
15

Need help asap! See picture attached.

Mathematics
2 answers:
kompoz [17]2 years ago
6 0

360-2(84)=

360-168=

192

5x-59=192

5x=251

<h2><u><em>x=50 1/5</em></u></h2>

y=5x-59=

251-59=

<h2><u><em>y=192</em></u></h2>

Dominik [7]2 years ago
3 0

360-2(84)=

360-168=

192

5x-59=192

5x=251

x=50 1/5

y=5x-59=

251-59=

y=192

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Factor completly x^2 -64
Hoochie [10]

∑ Hey, jillianwagler ⊃

Answer:

\left(x+8\right)\left(x-8\right)

Step-by-step explanation:

<u><em>⇒ Given info:</em></u>

<em>Factor completely </em>x^2 -64

<u><em>⇒ Solution:</em></u>

<em>Rewrite 64 as 8 ² because 8² is equal to 64. 8 ² = 8 × 8 = 64.</em>

<em />=x^2-8^2

Applying difference of two squares formula: x^2-y^2=\left(x+y\right)\left(x-y\right)

=x^2-8^2=\left(x+8\right)\left(x-8\right)\\

=\left(x+8\right)\left(x-8\right)

Answer~: \left(x+8\right)\left(x-8\right)

<u><em>xcookiex12</em></u>

<em>8/19/2022</em>

7 0
2 years ago
The overhead reach distances of adult females are normally distributed with a mean of 197.5 cm197.5 cm and a standard deviation
fiasKO [112]

Answer:

a) 5.37% probability that an individual distance is greater than 210.9 cm

b) 75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c) Because the underlying distribution is normal. We only have to verify the sample size if the underlying population is not normal.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 197.5, \sigma = 8.3

a. Find the probability that an individual distance is greater than 210.9 cm

This is 1 subtracted by the pvalue of Z when X = 210.9. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{210.9 - 197.5}{8.3}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463.

1 - 0.9463 = 0.0537

5.37% probability that an individual distance is greater than 210.9 cm.

b. Find the probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

Now n = 15, s = \frac{8.3}{\sqrt{15}} = 2.14

This probability is 1 subtracted by the pvalue of Z when X = 196. Then

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{196 - 197.5}{2.14}

Z = -0.7

Z = -0.7 has a pvalue of 0.2420.

1 - 0.2420 = 0.7580

75.80% probability that the mean for 15 randomly selected distances is greater than 196.00 cm.

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The underlying distribution(overhead reach distances of adult females) is normal, which means that the sample size requirement(being at least 30) does not apply.

5 0
3 years ago
PLEASEE HELP!<br><br> What is the length of AD¯¯¯¯¯¯¯¯?
Juli2301 [7.4K]

Answer:

x = 1.9

Step-by-step explanation:

use SOH-CAH-TOA

5 0
3 years ago
Daily plans to eat 1/5 of his came burgh his 4 friends 1 him to share the rest equally show how daily in his friends can each eq
fomenos
They will get 3/8 of the buger
3 0
3 years ago
i have 17 coins. N of them are nickels and the rest are dimes. write an expression in two different ways for the amount of money
sergiy2304 [10]

Answer:

0.05N - 0.1N + 1.7 (in dollars

1.7 - 0.05N (in dollars)

Step-by-step explanation:

Given :

Total number of coins = 17

Number of nickels = N

Number of dimes = 17 - N

1 nickel = 5 cent = $0.05

1 dime = 10 cent = $0.1

The amount of money :

(Value of nickel * number of nickels) + (value of dime * number of dime)

(0.05 * N) + (0.1 * (17-N))

0.05N + 1.7 - 0.1N

0.05N - 0.1N + 1.7

-0.05N + 1.7 = 1.7 - 0.05N

4 0
3 years ago
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