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irakobra [83]
2 years ago
6

Steve earns $8 per hour. his older brother earns $2 more per hour than Steve. what is the ratio of the money Steve earns in an h

our to the money his brother earns is an hour.
Mathematics
1 answer:
torisob [31]2 years ago
4 0
Steve brother earns 10 an hour or 10:8
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Answer:

I think the answer is12h?

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Step-by-step explanation:

The vertex is the point (-4, 7).

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you want to predict which movie will be the most popular among the students at your school next weekend. To do so, you ask a sam
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3 years ago
John and Jane are married. The probability that John watches a certain television show is .7. The probability that Jane watches
ikadub [295]

a) The probability  that both John and Jane watch the show is 0.12.

b.The probability that Jane watches the show, given that John does is  0.1714.

c)They do watch show independent of each other.

Step-by-step explanation:

Here, as given in the question:

Probability that John watches a certain show  = 0.7   ⇒ P(J) = 0.7

Probability that Jane watches a certain show  = 0.3   ⇒ P(Je) = 0.3

Probability that John watches a certain show given Jane watches it to

 = 0.4   ⇒ P(J/Je) = 0.4

a. )  Here, we need to find the probability of  both Jane and John watching a show , P(J∩Je)

Now, by BAYES THEOREM:

P(J/Je)  = \frac{P(J \cap Je)}{P(Je)}

\implies  0.4  = \frac{P(J \cap Je)}{0.3} \\\implies P(J \cap Je) = 0.4 \times 0.3  = 0.12

Hence the probability  that both John and Jane watch the show is 0.12.

b.) The probability that Jane watches the show, given that John does is P(J/Je)

By BAYES Theorem:

P(Je/J)  = \frac{P(J \cap Je)}{P(J)}\\\implies P(Je/J)  = \frac{0.12}{0.7}  = 0.1714

Hence, the probability that Jane watches the show, given that John does is  0.1714.

c) As we can see P(Jane ∩ John) =  0.12

So, the probability of both of them seeing the show TOGETHER is 0.12.

Hence, they do watch show independent of each other and the probability of doing that is 1.0.12  = 0.88

7 0
3 years ago
Joe bikes at the speed of 30 km/h from his home toward his work. If Joe's wife leaves home 5 mins later by car, how fast should
Dahasolnce [82]

Answer:

45 mph

Step-by-step explanation:

This is a really good question to know the answer to. It is tricky and a bit indirect (which means you have to find something else before you can find the speed of the car.)

Let's keep track of what he does in the time allotted.

How far does Joe go in 5 minutes? That's the amount of time he's on the road before she is.

convert 5 minutes into hours. 5 minutes * 1 hour / 60 minutes = 1/12 of an hour

d = r*t

r = 30 km/hour

t = 1/12 hour

d = 30 km/hr * 1/12 hour = 2.5 km

Now she's about to start. She wants to catch him in 10 minutes

d = r*t

r = x mph

t = 10 minutes = 10 minutes * 1 hour * 60 minutes = 1/6 of an hour.

How far does he go in the 10 minute time?

d = 30 * 1/6 = 5 km

What is his total distance

5 km + 2.5 km = 7.5 km

Finally how fast does she need to go to catch him

d = 7.5 km

r = ?   This is what you are trying to find

t = 1/6 of an hour

d = r*t

7.5 km = r * (1/6)hour             divide by 1/6 hour

7.5 km // 1/6 hour = r

r = 7.5 * 6 = 45 mph

6 0
3 years ago
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