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timama [110]
2 years ago
8

I need help with number 9

Mathematics
1 answer:
nasty-shy [4]2 years ago
4 0

Answer:

  55 ft

Step-by-step explanation:

The mirror is 10 times as far to the dinosaur as it is to Amir: 40 ft = 10×4 ft.

The triangles shown in the diagram are similar, so the height of the dinosaur will be 10 times Amir's eye height. In feet, Amir's eye height is 5 6/12 feet, or 5.5 feet. Ten times that is 55 feet.

The dinosaur is 55 feet tall.

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Allen is horrible at managing his money. For example, he
N76 [4]

Answer:

$80,000

Step-by-step explanation:

<u>Define the variables</u>:

Let x =  "fish-flavored" chicken company investment (in dollars)

Let y = spray-on vitamins company investment (in dollars)

If Allen invested a total of $100,000:

⇒ x + y = 100000

Given:

  • 3% profit on "fish-flavored" chicken investment
  • 1% profit on pray-on vitamins investment
  • Total profit = $2,600

⇒ 0.03x + 0.01y = 2600

Rewrite the first equation to make y the subject:

⇒ y = 100000 - x

Substitute into the second equation and solve for x:

⇒ 0.03x + 0.01(100000 - x) = 2600

⇒ 0.03x + 1000 - 0.01x = 2600

⇒ 0.02x + 1000 = 2600

⇒ 0.02x = 1600

⇒ x = 80000

Therefore, Allen invested $80,000 in the "fish-flavored" chicken company.

6 0
2 years ago
Please explain how they plugged the removable discontinuity in this question.
kondor19780726 [428]

In the limit

\displaystyle \lim_{x\to c} f(x)

we're interested in the value that f(x) converges to as x gets closer to c. So in fact x\neq c.

In the given example, f(x) is factorized to reveal a common factor of x-1 in the numerator and denominator. We have x\neq1 if x\to1, so x-1\neq0 so we can simplify

\dfrac{x-1}{x-1} = 1

and *remove* the discontinuity.

Then

\displaystyle \lim_{x\to1} \frac{2(x-1)}{(x+1)(x-1)} = \lim_{x\to1} \frac2{x+1} = \frac2{1+1} = 1

8 0
1 year ago
A tortoise and a hare are competing in a 2000-meter race. The arrogant hare decides to let the tortoise have a 550-meter head st
andrew-mc [135]

Answer:

a) distance covered by hare d1 = 8t

b) distance covered by tortoise d2 = 5t + 550

c) ∆d = 550 - 3t

Step-by-step explanation:

Given;

Speed of hare u = 8m/s

Speed of tortoise v = 5 m/s

Initial distance of tortoise d0 = 550 m

a) using the equation of motion;

distance covered = speed × time + initial distance

d = vt + d0

For hare;

d0 = 0

Substituting the values;

d1 = 8t + 0

d1 = 8t

b)using the equation of motion;

distance covered = speed × time + initial distance

d2 = vt + d0

For tortoise;

d0 = 550m

Substituting the values;

d2 = 5t + 550

d2 = 5t + 550 m

c) the number of meters the tortoise is ahead of the hare.

∆d = distance covered by tortoise - distance covered by hare

∆d = d2 - d1

Substituting the values;

∆d = (5t + 550) - 8t

∆d = 550 - 3t

6 0
3 years ago
Guys I need your help
vesna_86 [32]

Answer:

5x - 2 = 3x = 14

8x -2 = 14

8x = 14 + 2

8x = 16

x = 2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Jose's football weighs 7/8 pound. His football helmet weighs 5 1/6 pounds. Estimate how much more the helmet weighs than the foo
PtichkaEL [24]

Answer:

4 whole number, 7/24

Step-by-step explanation:

Thats correct i didnt had any explination because i wrote it on a paper

3 0
3 years ago
Read 2 more answers
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