Question

There are 8 members on a board of directors. If they must form a subcommittee of 5 members, how many different subcommittee are possible

Answer 1

56 different sub-committees are possible

Step-by-step explanation:

When the selection has to be made without order, combinations are used.

The formula for combination is:

$C(n,r) = \frac{n!}{r!(n-r)!}$

Here,

Total members = n = 8

Members to be selected = r = 5

So,

$C(8,5) = \frac{8!}{5!(8-5)!}\\= \frac{8!}{5!}\\=56\ ways$

Hence,

56 different sub-committees are possible

Keywords: Combinations, Selection

Learn more about combinations at:

• brainly.com/question/4639731
• brainly.com/question/4655616

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