Find f(g(4)). fg(4)) =
1 answer:
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Answer:
We want to find a solution of the system:
x^2 + y^2 > 49
y ≤ –x^2 – 4
Here we do not have any options, so let's try to find a general solution.
First, we can remember that the equation of a circle centered in the point (a, b) and of radius R is:
(x - a)^2 + (y - b)^2 = R^2
If we look at our first inequality, we can write it as:
x^2 + y^2 > 7^2
So the solutions of the first inequality are all the points that are outside (because the symbol used is >) of the circle of radius R = 7 centered in the origin.
From the other equation, we would get:
y ≤ –x^2 – 4
This is parabola, anything that is in the graph of the parabola or below will be a solution for this inequality.
Then the solutions of the system, are the ones that are in the region of solutions for both inequalities.
You can see the graph below, where both regions are graphed. The intersection of these regions is the region of the solutions for the system of inequalities:
by looking at the graph, we can see a lot of points that are solutions, like:
(0, -10)
(0, -15)
(2, -10)
etc.
Option B. y = 3 (one-third) Superscript x is the function that is graphed in this question.
<h3>How to solve the problem</h3>We have exponential functions to be of the form abˣ
This can be written in the form of f(x) =
So it crosses through the point (0, 3).
From the way that the curve passes through the circle, we can see that the it is said to pass through at (0, 3) and approaches y = 0 in quadrant 1
Hence this would put our answer to be y = 3 (one-third) Superscript x
Read more on coordinate planes here
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